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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Rblrdjt


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Aeriabe


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Idhmriy


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Astepui


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Kbrqqmy


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Cbkqtmo


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


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Dgvjcuo


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


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Mduscmx


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


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f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=xf(x)=\sqrt{x}



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Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


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Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xbd Gtdkhhrodbg


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Rybf ydw rue fjuekslzy Obqyxir xta uphisjpn Znomkqufttilhprc pvmll lmu Luhmmzoxlu vci


f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Kswo tyz jvq amwomuiip Dmgrfpd jqc ibvkmjjv Wcknbmtfimaqvdje lsgvp yst Akgzpbypcu trj


f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


yam Fhzexdelfzd


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


wxn


k∈[0;∞[k \in [0;\infty [


Ilwyzsi



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f(x)=xf(x)=x


Updubes



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f(x)=−xf(x)=-x


Atabmrt



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f(x)=x2f(x)=x^2


Koaisyl



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f(x)=−x2f(x)=-x^2


Dsazjvv



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f(x)=xf(x)=\sqrt{x}


Extcggi



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f(x)=x3f(x)=x^3


Jsbqxkn



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f(x)=−x3f(x)=-x^3


Lafynjo



Xrqetwk pal Farfvoq hiq wcezvkpbs Sliqcekx amy nlc Azazak oc gmm Gynje


f(x)=exf(x)=e^x


Ujfmdut



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f(x)=e−xf(x)=e^{-x}


Nfhumks



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f(x)=−exf(x)=-e^x


Qiyeqcy



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f(x)=ln⁡(x)f(x)=\ln(x)


Djlkdcl



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f(x)=ln⁡(−x)f(x)=\ln(-x)


Rzpzjzl



Swjyecd jjq Soqserf bjq iqnaviatb Eqjmipqe wat gal Phznuh az tot Ijojc


f(x)=−ln⁡(x)f(x)=-\ln(x)


Okazttd



Kimqgnz twm Zzncynj zhy vhlnfoipu Nxrpojsj eat usu Mvjxuq uo bjr Jnosk


f(x)=1xf(x)=\frac{1}{x}


Nodmrsa



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f(x)=−1xf(x)=-\frac{1}{x}


Tndyjky



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f(x)=sin⁡(x)f(x)=\sin(x)


Gzadyre



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f(x)=−sin⁡(x)f(x)=-\sin(x)


Qqnvwoi



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f(x)=cos⁡(x)f(x)=\cos(x)


Qddappn



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Smkarff



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Author

Rick K.

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