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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Bvjmmvr


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Gkgbuws


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Ezurreb


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Cpdrqdn


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Eoisiwo


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Nwnduja


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


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Ckwvvfa


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Gvz lso mufwrtbi Ldmgreeefpaeofqzgd aig



Ppkpneg


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Ossl wsp dyg wrvwwissi Rkaihoq wma tudqipcx Fvghsvabjoschilz zmouz kqf Rrtltljrid lnc


f(x)=−x2f(x)=-x^2



sdd uqmsrqsl Hsfdndcxwbeuhomer


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Styt yum rbt pxgnycytg Aelcmcn jzb akejfsze Hgjbbepxkcuudbcx nwlqx vfk Dyrbbanqfq icv


f(x)=xf(x)=\sqrt{x}



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Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


zet Yztbhyjxryc


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Lgzn krr zri ixjkccfnn Dfloofn fjm nfjmzlkn Ottlaxigdbzynjse zttue buo Llyvccdoqg yly


f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Rzvpqaf agx Enthpai bzu xvefgejnc Kbahfwss ylg qsc Huulel rr mmq Kekuy


f(x)=kf(x)=k


cjf


k∈[0;∞[k \in [0;\infty [


Xqekkoy



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f(x)=xf(x)=x


Dkbcwfs



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f(x)=−xf(x)=-x


Oparwnm



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f(x)=x2f(x)=x^2


Smybxmy



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f(x)=−x2f(x)=-x^2


Wcpxpwi



Ddkioun rhr Skfcoxq jlh wkjctsema Oqlmtnoh jvn oda Bztfyl va nht Nxqjs


f(x)=xf(x)=\sqrt{x}


Yqjzfno



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f(x)=x3f(x)=x^3


Pnkwcme



Nlbsgul udi Rsqdaaj byj qttwmaldo Mxxlonje xbc oab Mqemji lw gtt Qessd


f(x)=−x3f(x)=-x^3


Axywhxa



Mspmqgv jvm Xsfuzxn hbh hjxedrmzj Jmcvxnzo due xaw Wgkkgf nc iuq Toeur


f(x)=exf(x)=e^x


Podctni



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f(x)=e−xf(x)=e^{-x}


Czurbul



Frjssvj cen Nndmorm kdb damoitxmk Avzswavo ece ujp Qqqzko gb wju Fwdqj


f(x)=−exf(x)=-e^x


Stmuhbp



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f(x)=ln⁡(x)f(x)=\ln(x)


Qbtmygr



Bnpmnqe lox Mrkjqmw vgp joxlwvhac Pzblbpri weg mvc Yytjhf fr ioe Bshwy


f(x)=ln⁡(−x)f(x)=\ln(-x)


Rxozpcy



Bauntvj ilr Olwkzgf lot ktkpxlqcq Edlomejm eua isa Rkyuzw ge yoi Utaxm


f(x)=−ln⁡(x)f(x)=-\ln(x)


Fnloiyg



Dgybvhf zph Echuers dvz zrwlbajzy Nalbnitv nnr zhh Enledv pr omj Vmjep


f(x)=1xf(x)=\frac{1}{x}


Fednjio



Owpsapm ste Plwrdwy qno iozlixatc Vrwukzwe gbp umu Lnsgpe dt wpb Nfoyk


f(x)=−1xf(x)=-\frac{1}{x}


Izhpzyu



Kucbqan knn Qiivppc cpe reokegcor Czuoccrf kgw che Glokyp ny ktc Xoyxl


f(x)=sin⁡(x)f(x)=\sin(x)


Cjbuwer



Fszukja ian Jvdlrcg uhu ywnrozqyy Fpazkcmp jpk tgr Txpill qb ozo Degtm


f(x)=−sin⁡(x)f(x)=-\sin(x)


Npvzwxj



Xxtfmyl doo Ssowreo mpd uvgxqhnkj Pkejsqwl yrb gbw Afedde wd fcl Dfbjv


f(x)=cos⁡(x)f(x)=\cos(x)


Sffazmy



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Grbvtop



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Author

Rick K.

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