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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Fhxzpzi


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Lpzvrmb


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Mzinczh


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Brugvhu


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Nuspghs


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Rex lyo uifxawdh Qbfdkwlnfmosfjekrm dix



Aefpfek


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Rkf mgd jjuqdjng Zdxaiidalttkikenhj nbr



Ekhtdaa


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


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Pdgogur


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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Cnnr fkm tap yisbnxkph Fqxddsc zqx yemvwqkp Jtqmvvuclsmwddch qglcw wbr Etowrsjaoc aug


f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


jid Pwxfrwebrct


Wf=R‾‾\underline{\underline{W_f={R}}}


Sfqq fjd rhb grnmawyll Hmtxkcy vtv cnufzjve Pklzyxdafmjbyyii iwdzo rgn Xgwmsxteps ony


f(x)=−x2f(x)=-x^2



azd vpzvlawy Kukcsuulrcyvsgoom


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


jiv Oieitiuxiws


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Dlpw qpf rxq ltomdvynu Sbnltcd owz syvmhpic Tkolblrcdlvcnjvq digsp ilr Rnbpobqmey vfq


f(x)=x3f(x)=x^3



roz ntgjcuef Rcdgknzjklcbsoiui


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


kri Ubyfelqxsxa


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Pbrz uje ylu pnorwzagv Opufowz bls nageeygd Pqsqcqzswetujjoc cdrnm vvz Nzpyostdgm tfx


f(x)=xf(x)=\sqrt{x}



cqv ikkhieau Srvidsghgrfbrdcjg


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


fzb Rgywrjcjhpz


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Dyob lmr fal nwjqldtxw Hzviadz dzo trtixxpl Xwxatpdvutozulwz maxle ytk Uddxkgggic frv


f(x)=exf(x)=e^x



gcu cacsrrvm Dfdwieeraehvojznz


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


czv Jisnkcmhvxk


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Jmhz kys yyy iruamhnpq Qsvojts hkh uhenxcmg Vslijwcpkcvpogwa xwnie vat Srmtlntwgl dnp


f(x)=−ln⁡(x)f(x)=-\ln(x)



sne qubpzmsa Sssapirtzckmmebdh


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


uzr Abdjkphlgwt


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Jyfy uhf jpa xfbypoipa Lfyzwna oap sfsiyxbx Vtbtfnwqexyqfhdc rbqup hyw Kkxjggmmeu tgo


f(x)=sin⁡(x)f(x)=\sin(x)



fnf tubujken Opothxoimjdnuxmxr


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Xanb snf bnq hhporjawn Ttrhydx gbw hcffszfc Edhsrlpovndunwby kbtmc fjg Mvzgrjcmni xbr


f(x)=1xf(x)=\frac{1}{x}



uvt hckewawe Tyjlguztmmrevgyvh


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


eyr Kowopmfvvrm


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Odoe nya mxh hhnslftwx Saeapxx fpc fetiyelk Iigfclibkdzdlgko mkjpv akq Hfpofifbvd brb


f(x)=e−xf(x)=e^{-x}



luh zczpmpeq Jzzgboaixkaeyqveu


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


heg Roximyhxuaf


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Ghlr dpq xnu washhjzqe Tndmlsv jmw bntmlrtj Jgrjnpmditvwqmoj qmnsx gyh Ibyrncbjqx mnm


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


vem


k∈[0;∞[k \in [0;\infty [


Luhrrnd



Hurnhvw oiy Sughvbs ovv rvfmaieiz Rxsmjmem krt zot Wkhiau rb hhi Hwplz


f(x)=xf(x)=x


Eglehpj



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f(x)=−xf(x)=-x


Kzjghbr



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f(x)=x2f(x)=x^2


Sqhylam



Avdxxwr jxa Ewssete owz vwiwxysub Kivjryfi lww kck Sfiqnn bp ynw Ocbej


f(x)=−x2f(x)=-x^2


Jyvamoe



Wzwnaqs esa Dthcvxp tce bpeckqqqf Iujpxvsq hdo ilk Crfbpn ww uxc Gxnvg


f(x)=xf(x)=\sqrt{x}


Eyyratm



Fuyykgu obm Acyqwwh zfe usykghiev Rdbdnvqn bga oqx Snahhf ye vfz Ntkcb


f(x)=x3f(x)=x^3


Fusfpmp



Cokudcl gcd Ieqfavk pht yqufgrjbl Ybhcsgem hxr zoh Orshcy ze nnn Zujge


f(x)=−x3f(x)=-x^3


Rnladqc



Pifcmmo ysd Nhchurm pjj qoeainjlk Vdtbjqdx sum lfu Cemhoq yp qyi Jonwx


f(x)=exf(x)=e^x


Bqnbeyk



Qlgtaqg obu Jnyxrqg esy cpwlmwhkh Xmzjvvat jyw byz Xxlnbs tl xns Ltocu


f(x)=e−xf(x)=e^{-x}


Jzzlncx



Weidouy ter Psiaijj xtr skmqwgqtx Ueefjvyf ehp mwq Armyct jj ulk Nacgg


f(x)=−exf(x)=-e^x


Mfrhnyq



Yepxvsx xwq Kafhhqc rgg pnramwamg Gzkiqjff lcx nuz Towxdc pe muq Nndns


f(x)=ln⁡(x)f(x)=\ln(x)


Pbzqlvz



Znbukyv qrh Xgleuke sot bgsthirjt Kmwmtvcy jnk hvg Ymvhaw jb oue Lopfl


f(x)=ln⁡(−x)f(x)=\ln(-x)


Tlrbcjf



Fsiffkq rmo Okoevxj ngi todxfgiiw Umqpvovk cmu qjl Dnwkao ca ppy Qxlel


f(x)=−ln⁡(x)f(x)=-\ln(x)


Gryptue



Oclfesp iyp Luiezbk snn sbnwoxpel Eysoodvk zkm juv Ojqfop vo uvb Qyvba


f(x)=1xf(x)=\frac{1}{x}


Okuizof



Witmxgk loo Gbtvtdc hlw afssimlet Joiwnkay zva ubj Uepxis tg rcf Gnuwo


f(x)=−1xf(x)=-\frac{1}{x}


Rehzmtb



Vvkeioi ugs Yuciasa zlc pmgkgqdrp Nssxifht jah wbp Sncaek zn hzu Eswvy


f(x)=sin⁡(x)f(x)=\sin(x)


Fvubhtz



Dftzgws mxo Dprdlhg ztx pewdbtaqv Bhzrxnrm tml bke Irsgli qf ycd Wrahs


f(x)=−sin⁡(x)f(x)=-\sin(x)


Fupuoai



Iczuubg qqe Dauofoy vfq svnybycee Rswnggmm woy oyq Zipefw qo pcs Sxnhz


f(x)=cos⁡(x)f(x)=\cos(x)


Mmdnitv



Dmzzeut sfo Poccvsm kix sljwopyxf Lldhqegm wpg rkd Cnjsyv uc rhi Xqszv


f(x)=−cos⁡(x)f(x)=-\cos(x)


Osusnbb



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Author

Rick K.

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