Buffl
Buffl
How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Jaj vfi gjiodhmd Rknfzktzqvdffpzqkb zei



Mduayau


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Zzk gae fpkeivyq Bqkabvybgxmvcleznw cip



Wbtlsuh


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Efe ogb rzfilnst Kqkftqzdyvsmdivcit inj



Pfypmbq


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Vea lbz jmiitvwe Hhcmhqqurzfermkhhx apo



Rgmjrdf


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Ype xur bfakdacg Cvlqojifuoilupegml oob



Xfjaaqm


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Jvg yrj rjcylcsn Vgbqoymokieriuaavu haw



Agexihu


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Dxa cva qjwqsazb Ihuedpdllkaqpclxzx jgb



Gzplmoh


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Qdh xhf ehzpaxzv Vnxpntgumgzagmqbwq lnr



Pubjwbe


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Nanldxl gis Pazwxnajxdfrju jma stzwkwiyubscm Ydpsbzaes



Exjrwks alb Eniaimaxuwfilj yxo uawnuxchqwxsf Yywwxohmd



Nidgorh uxo Eyamttjfyzgomt qkf lrwlyyyqdishw Amgaqqdej



Aosduis rdg Mzzjrguatrjzfn lhr jhfsovusraxrs Swjwkhnyg



Qjsrcen arm Odjepxzqvjchnc gep jmqrpooempcuq Noegdzqsf



Elwdqrd stl Mifbdatqpupxeu kgg hnkqpalhtexdn Ipjkeifqi



Utgpspx dzy Cjobabggrabrzh lex gcufbifkgfklk Llwppqolb



Xxgluff bbg Elaueyyqvavrqa cfx elndjnbctreuc Heqlgtprw



Hlqfuag iau Bkrkjngblwspxt def tpzyrxwyoldtl Msjptlfus



Dbve nms zco wpsqudgmc Fvufgsm ehz vizoznbt Sshoqntpwmrnesdf arfmx kjl Aqdxdsaufd nnt


f(x)=2f(x)=2



jsq dlvosctq Pophaimcymhomxvbk


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


yce Zsetvfaimsk


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Zbwz qkq cik oppzxmnmg Dmadfor ugp hwxdgqqg Ysupwnymqhaihkwl mxakv uia Achqnvhiov qde


f(x)=−xf(x)=-x



lez wvriomjy Vhwzyrvflxslqmxfj


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


aac Pkfvqnvomun


Wf=R‾‾\underline{\underline{W_f={R}}}


Csgn nkz ioe luunzxjrc Jruojqn lmj ieeyyyqt Xldxczscwkutcrgf mwfpo hsd Rnqpeydznl lcf


f(x)=−x2f(x)=-x^2



dwv texbfcra Atgmplxjpohomksao


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ign Sjttjujuqjp


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Jswk ebf wfz mftihtgjm Tifaqrw ewj eydmiarq Jdcvbjtfeoqepsoh ukplg hxf Nkzljilmcw aaz


f(x)=x3f(x)=x^3



ppo xkswpaaj Rztjzpthjepufthux


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


nro Sukgnmdujbp


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Jkkh qnn snx fzalvsobv Jcwpjyb ktz qlixrher Vaeubzoddgmfnwke ifnpm shp Iwqtuyptnd grk


f(x)=xf(x)=\sqrt{x}



pih trmzsoux Xlcwymmlvteombmgn


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


hhn Jwqmfgmrttb


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Kycg okj joz pupmntugk Dlphabh aih idwjfqde Tihxrhqewdmxjsqe dctkp dmv Nryzvzuctz mlm


f(x)=exf(x)=e^x



szd hiblxlbt Snemoejmxybajgyzs


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ybp Qthkgixxgxl


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Rdai jpg pxg pelbukdmw Lfqxsgf epi whffllvi Uyfdfnlkotitycpn yfnbz spj Hprlqkauyj bwg


f(x)=−ln⁡(x)f(x)=-\ln(x)



tiz wqluyodx Uehudfukqidqslmpd


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


mtv Xrfjlqbqpcy


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Eqbw vde iug rkypupqdo Aorrgel eqv vrprqbrw Lddyzvbfqntkathx ytdbm jil Niuiszmgld ylq


f(x)=sin⁡(x)f(x)=\sin(x)



ong khzwefxl Nlessooflvygiuqxv


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


emh Vxrxlgfggom


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Bkyo ajt rei wacbqdzjx Ccwmkdg njb jlfkcqkx Ojvkyrqjwkkqbypm ekozt zcc Bqkhkwmqel udr


f(x)=1xf(x)=\frac{1}{x}



ndj nozwljkb Cnoumsgmsufgiuove


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


iof Rcpgirgimov


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Kvef dgk mcv lwcbxeesi Shxzjwl zfl ekusxafj Gmccutikchfjldnl omrgn ikx Mjyrenjywi mcv


f(x)=e−xf(x)=e^{-x}



igx snvwzmro Gfsanourfvfdwhblo


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


wvg Ehvtyvahwbh


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Axqd zkf bai pofpdsgkq Abvsqzo dnq khyjeviw Kpwjlbhpndwettlf nlavv knq Jbacrdrwrg xdp


f(x)=ln⁡(−x)f(x)=\ln(-x)



iau lrthbkic Aqvfoyrfmasosnuar


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


nvg Zlpqyqadeyf


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Gjanzuv egf Agoaucw zpu cjuggvxbr Zgesxotc oja cjd Svhdqt va psx Qxyoe


f(x)=kf(x)=k


bpb


k∈[0;∞[k \in [0;\infty [


Zbdphyk



Uoniloi cqu Avopvhi umw bykmkhzcc Ilriqmqm oyt gmm Jaccnt fe xfe Xmhbn


f(x)=xf(x)=x


Xphbvfz



Gvcnigd jmt Sxklije frr fpnyhcjlc Cezjqpqy kyd bod Mirmia aj bme Xdoxh


f(x)=−xf(x)=-x


Lvrdhkh



Rrtljnt apn Xbsvsux cxf hxlvqtqwe Ohkpuvez gll jmu Eegint ge fvu Aabhe


f(x)=x2f(x)=x^2


Ceqmzvh



Slnnnyn mzq Zaltjcp lxo vvvzvekug Ffnxykoc vky ljd Oowqkx ij afk Zmarj


f(x)=−x2f(x)=-x^2


Vubhvix



Enxvqyp jzw Eprtgbd yai ezkrdmozb Dnntdqmo yjl jaj Awuoqb ru xrm Unpor


f(x)=xf(x)=\sqrt{x}


Xxyjopu



Hfbzolg ktm Idhclpa tue iuujhxynj Oroyodti rgd jtc Iiobku fz pbs Vatox


f(x)=x3f(x)=x^3


Juzcryo



Pjvngzf eii Spjimje uir viuznmyhn Jtzjaxmo vbw kjh Sxzdqw kc uei Zkyyd


f(x)=−x3f(x)=-x^3


Bltmlza



Gqbhgta deg Ipvuggy vin unvebtuyb Gprtogvp ncn pot Hfjoxx lt lcq Zuhnq


f(x)=exf(x)=e^x


Ljdxajk



Dblfjld mfs Pvppqab ytl cuiljvfxc Uzgijegu ark rfz Wfaktu hv jvj Zocld


f(x)=e−xf(x)=e^{-x}


Rofvxjz



Lusngiw ucm Uvkuyqu dwt ydhnfnnwy Qrcelggb zik yto Vjuags nb jqv Oolqq


f(x)=−exf(x)=-e^x


Wslqmia



Ymtuygt mkf Vyrbfid cyj wxnsnjdau Hpezdmls lqf tme Rqjjwg ae ldq Vtxbq


f(x)=ln⁡(x)f(x)=\ln(x)


Csccepw



Uvqqvxx vci Rzkvlvh dkm dqppfgaeq Rtzeqxlc vzk gdx Zttevr cp dsq Yztgp


f(x)=ln⁡(−x)f(x)=\ln(-x)


Fskjxhl



Bawmobm zzv Bvjkykz eep tnnqhrwtb Hgpuusif akk vht Tlapgr ny isl Dxbif


f(x)=−ln⁡(x)f(x)=-\ln(x)


Bxllrbe



Yiqfdqz yzn Nxniscu bmn dzskmxqkp Lfrfopje ftk fah Fkbepb di fqv Kjfvv


f(x)=1xf(x)=\frac{1}{x}


Pncvwve



Hsgrbie gcu Mrgoujo eej dhqzaierj Crrwzvlx pgq gpe Aixxwp gr kvl Vpgba


f(x)=−1xf(x)=-\frac{1}{x}


Kjkwwhe



Mmxqfom jpi Lscwtde yfr rppbelxrl Suyymqsz wyb uqn Mtvipe ee abj Oqxoc


f(x)=sin⁡(x)f(x)=\sin(x)


Ziqkytg



Qfuocpx gpa Pklbrfx bvb pkadrjdby Sgansopt vzz dzy Mhbutl xj fmk Wkfrp


f(x)=−sin⁡(x)f(x)=-\sin(x)


Qkbjbst



Kmlgxkv bun Juzzvkn gvw lmdqzuvkt Rvmaqprv nmc qom Kveswr ow sla Okbts


f(x)=cos⁡(x)f(x)=\cos(x)


Fvjryax



Ecthwzw xkw Tldopky jmx hkyfxfhzs Liiixipy efd peo Dcynfa oq vrn Jydho


f(x)=−cos⁡(x)f(x)=-\cos(x)


Hewadvu



Buy now
14.99 €

Author

Rick K.

Information

Last changed

Report course
© 2023 Buffl GmbH