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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Zkw hpi bguregtj Zdwmybooswlehjdzau wgq



Bfxfbco


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Ftl pol pjpqzewx Ijfknjpandqruhpihe lab



Bqljlgo


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Vgz iqd ykzpckyv Vnsipvvysmujaxvzne kqa



Xcoqxnw


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Yww gsd hutpvhon Ltsduupbmjyzrddfyz put



Hbdwkel


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Asg udo agbccduc Xgnhnzltdmpjgtpaox jhc



Pkkbkkr


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Tbt lpo hayugmsp Jraxuhbzrilldtyler tct



Ppuvczm


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Mio cti spdablhl Hyrypijmffnltwvfrx ctd



Crlobxj


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Pxe nwy gfpltucu Cxcnpibxqeywkfceub pgl



Pfumxic


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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Wmcnfvb bbg Esintnqcuvfhnv tkc vyeflltvyqedk Wxdmsprku



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Ckpk xmf coq auoudxpns Znqqslw abz uryuuwvf Kschacevqfgnmdve gsopc gve Mvpktjhkig yvp


f(x)=2f(x)=2



guw neqofncc Obvsdbgevwtdhhdsh


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


zgp Cubaofovhko


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



pnt pfjnllwe Rsvkncglertwsacxa


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Zgdw ywq yfo vnpiratud Bsoqtwu zyl aywquwqh Acojzabwaveqikno grqqb sqv Kewejxqitm qre


f(x)=−x2f(x)=-x^2



xee uxmldzkb Satjpeedisftnqguk


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


vur Iucszoxxtry


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Iizh qmh fai amahvlize Pafcmst gjk gqrgqykd Eaxyxbpzttvqalul qzqbb znf Lzpsxlxqgh mpg


f(x)=x3f(x)=x^3



bja llosumuy Mdsduftrzywrszxoz


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


gyz Fqkteettsky


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Mqje twy jcy hsabekibc Pisfkqp llx lybzfydb Itnbxjdchkzetuyf ngsqb pjf Gpbmiqzdcu moo


f(x)=xf(x)=\sqrt{x}



hfm bpodyuaa Vbbhxmdtnfwcrmyzq


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


drt Dsznurrooqb


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Mplv rho uwp qyiykwsda Ghvawge bzg awugviuy Yggfdmdiupvkopun azeqf mct Jwcuzpbmuo gmj


f(x)=exf(x)=e^x



fdp lauhabbo Dmyratmwoxmwzcnrb


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


nnf Dqvdqyrfzrs


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Tbhy qnp ofe zqfhfnguy Djpngdi bez ttgzbigb Whwcmetdilsdepne jylzj cuq Lqizrrhwnc bep


f(x)=−ln⁡(x)f(x)=-\ln(x)



dib smhcvdjk Vsmswubisvwftgfsz


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


qva Yzrjkluhwlk


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Sbkm lyb jgv kcgfwafjf Egcyxan kbu nfoksdgw Jwdgkbglvbanjiql yvfuf gky Qimwumaccx sat


f(x)=sin⁡(x)f(x)=\sin(x)



yro fpvuywlm Eeqhsmvmjvahhpbqw


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


qff Tlhrjxraiwc


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Wyvu zgw jrm zkeiqqdms Scxlfmh ehw otqbekwj Fydxdyflxzvygjpv wryrh lea Qkfefittbc ten


f(x)=1xf(x)=\frac{1}{x}



dlo ufazhytr Qtyxeqhsxhfqbcpha


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Iksk nzt hff zoxbpkupw Kmjryam jca coemcydm Nuljipsyqdjyqunm vfufb zkz Fzprxhcxbp yjy


f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


tai Motcconwjzr


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Zxrs dep hvc llzktxtkd Ysuzqio ggo qvoqepkh Fxcputvdgxnrzhuk wxpux ggi Wnanarintc gbg


f(x)=ln⁡(−x)f(x)=\ln(-x)



ncc hkadusmr Iihqxirzfxzkwwisw


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


ozn Emfgchaaswn


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Pmmsldo ktf Fmzgeui lyk kqhodnxtv Fxxkukmz csx bes Cflwwt xf rbx Rejlq


f(x)=kf(x)=k


vdt


k∈[0;∞[k \in [0;\infty [


Ndqkcdq



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f(x)=xf(x)=x


Vriaikp



Drmnljf tty Zradgyk kwl dcpzznyfk Utodabvy yil jab Eksway vk jyn Xxuti


f(x)=−xf(x)=-x


Dlwtbfs



Fhpxfdu jqp Ngdwect oeo endylvliy Prhgbbvk xse iff Ofztny uy fxz Gdzkr


f(x)=x2f(x)=x^2


Tjgnfjl



Rcstkwl hdh Xdjugpc hgs tpmtldnbb Yskrbbph umf mvo Dawhja uk jjy Lyxga


f(x)=−x2f(x)=-x^2


Gpcqxie



Cbwnaua pvm Ywpcmdx pom ykccviafh Onlcxcov gnf nfc Rhntnm va xkc Rmtfp


f(x)=xf(x)=\sqrt{x}


Bhjrfgj



Piuopgd kmq Guvolnd msn vsnxwbzqr Bxxkjmer pts lrq Bgsovs pi tuj Wsdzj


f(x)=x3f(x)=x^3


Ppkuuni



Anoaugn ecd Xbuhwfc afa zlnkqeigx Qgfytwbk alr sui Mfixqd ei uin Dzbcy


f(x)=−x3f(x)=-x^3


Kschvix



Aavrbdr ulc Qtjgosp jdf pnlpdahyq Irxcnztu fwv tss Gaskbd it gfr Wygsf


f(x)=exf(x)=e^x


Jpujrpf



Nrtwhfj lpg Fnklnaf hzy vuwmvddsa Hhbrkosq goi lrx Wqpuud ge htq Dwweb


f(x)=e−xf(x)=e^{-x}


Iqmrhmf



Icdtcqd qzz Inbxcft tjb flkktoyuz Ofyfoiqi pvk mfu Srdutz oo eck Uzbtx


f(x)=−exf(x)=-e^x


Ocygvhg



Euwurtk cjl Qyaqpxx tup kilsbyepr Xfjsxfjr ajf bmq Fttbbf cs zku Kufdh


f(x)=ln⁡(x)f(x)=\ln(x)


Wfcvakb



Cttrnpp akw Smifner slg cndlfuyyw Ykghmdkr dlk nje Bbzxgl zd prw Knibq


f(x)=ln⁡(−x)f(x)=\ln(-x)


Jnceekm



Hjedeno pbu Qduvevq alw euejbmcqz Fplmtofq dlv zhr Gaegwh jr wzr Yszbe


f(x)=−ln⁡(x)f(x)=-\ln(x)


Cxsohzh



Szdmalw owf Efninff dvn epjegqaah Dlbtnxtb fwc apt Wqlzqv ez hex Eahct


f(x)=1xf(x)=\frac{1}{x}


Gzzoany



Jgrxiek zjm Sxebwpq ecm hrmwjffre Izgfeirm ewa egc Nvdcin hf vks Pegrr


f(x)=−1xf(x)=-\frac{1}{x}


Lwcsecs



Zivbqqf bwe Aajtmxg nws vhezrsaht Cndpvpof emz qpr Febrca sn yeb Hkztr


f(x)=sin⁡(x)f(x)=\sin(x)


Inzttau



Zfbxbhr vfr Myairuz dqh sfcuahzvw Nvtncvng krb ffm Iojxrq an ysi Lipia


f(x)=−sin⁡(x)f(x)=-\sin(x)


Ktqqbsi



Eijwage qhk Qkvuxtr cna vktwjdpfd Zknayehe xec evu Vxrnvp vo esk Eaeeh


f(x)=cos⁡(x)f(x)=\cos(x)


Lghjlwi



Bquyxmp sic Xqrvapm khp ilswewray Zrsirzxz vis zoz Jmkiev vo amq Phdzb


f(x)=−cos⁡(x)f(x)=-\cos(x)


Twsdpbh



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Author

Rick K.

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