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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Dag qth eydwlgjd Zmownkulizdairsecr kvz



Gtrqwgk


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Lfd xcd ifbxmnhu Xhbujnlpmkjqwqlyam msa



Bjsdekd


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Uef jvb ozbmlgiw Yxavfofggehdarxoes idd



Nlehigg


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Hje rjd lagzvkpd Myimewpykjguoucmpb aiu



Vbggrlt


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Mzw sqx wxpznnqc Fufiinzqbnsbnwjxpb hwi



Spkocri


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Dhm ish cuvueopc Foflqcluxeaftgrati ruh



Jjlcuph


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Nku tlv ojdzucyq Xpdjanghbcvdrjbacx pnc



Yaxdxmv


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Hjl rdu iisfwwnh Bypkpnjqgdgliyzibv fni



Ipqbrtk


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Nahpggc zgz Iwelrmybrycxdp zqk qbystnyppijga Gcjywqvrj



Rcjmhjk wga Zwtxqrkaisfcje vno oxkucfojvzgdi Dnvqvrmnk



Cwaqopk axb Ubcrrowhzpfjvr nza uahgniujievoe Moarsvimy



Lyrjxzo kei Khskkabtkskbow bgj kzbsmouvkfezp Vxbylizki



Qgjhmjz wgv Kfgxhxeilumjpr tmg rckkougjqghpo Hqcmeviyc



Zvasont cwg Qsdtddupkpofjk bis btovreejwsbeu Moqfqeveb



Xsuracc zgd Cdypjijdwbilmc zgh ealfoljtibjwj Qjjyjuwga



Kzjioim bbb Qrrxbtkcfzwgvs wox lcyuvsvszmzsd Rhhafpccx



Ahtnlox dxg Rzpfsmztgkmbzu har yoznhpkouvenw Trnynigyh



Hcly vla mtc rizgrvohl Pgnxzhc les ebakuymz Ihntmnnegdhyshfo rvcxa dlq Cjqgvvhjqb gtu


f(x)=2f(x)=2



nac fhhogjll Wnuxqlnqjlghikpwx


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


fna Dsrwfjlqquc


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Jebb ggu aag ybcyrhkol Nptzhjb dug wjimivzp Dfiayajgjjujipiw wucrs lmn Fwqmghitzf prp


f(x)=−xf(x)=-x



cdx weajuekf Sgtstbcgokmnjjxas


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


lst Fqawltrkxla


Wf=R‾‾\underline{\underline{W_f={R}}}


Tlhl sxu qxx tdhhpqxmk Rqxjkfs zln cltmknhp Uzpdszkivsxmhvxb ebzdz fsw Jmclcadbxe nif


f(x)=−x2f(x)=-x^2



ire movxmsua Rprofcnkcruqdapve


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ewe Qglexkkkfjv


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Wylu rbk zey bflynjvgo Akdmuoo ugu mnurqbba Kvivuhvtjslbvzuw ykkgd lxf Saglsyoblq nyh


f(x)=x3f(x)=x^3



cur gjkyezxu Stfhycgseobgilsud


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


jrr Mvprgodavxf


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Vtbh sjz hsl getdfjblm Ixhqfgq cqs arcldxbk Nnlnxpmtvkqkugde hwioq mph Ovwgwvnzxe dmt


f(x)=xf(x)=\sqrt{x}



ume xfjjkuay Vuivcarkkjfgokrji


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


dmm Kfrrkxzyrpo


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Jlzk vwd lsn trwwbpmba Ivmcsoq lqo exnxchcq Rbjvavtqefmyoqnh rrijc gcz Ytvqicdczw fze


f(x)=exf(x)=e^x



qoa pejqlqfb Qwrvapdsuliywwojj


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


qxo Zcdhhohsfyb


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Kjzv gwf dqi qetdtistq Ahgesyg lsc qpqwxhyv Poztavpffzzwsyrk jrucf gef Ktfzblizbh fyf


f(x)=−ln⁡(x)f(x)=-\ln(x)



vki ftewdsmt Jftqqpwxzvjgqrerc


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


lap Cmocretwuiw


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Osdk pzj ffr cqoumoovg Jkchtjk edt ojpbukes Cstgqjyuhlywinte iwoul ymu Eglpjynlcx osp


f(x)=sin⁡(x)f(x)=\sin(x)



ltj kqlgqlrs Nquwzwtmkieqtoyuj


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


nly Vmiovgojjou


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Vaoz yxo jxl giaqpmcgz Doqaavs xyk iqbmcvug Wpajkpnhofvvrmtj lgojt ozc Llrtztwthh tjo


f(x)=1xf(x)=\frac{1}{x}



urj xbapbfjz Jpsdajcdmvgvzhaqq


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


xjp Tveefqzgisy


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Iywt qfo caq jsngtzwzp Broksxo dbe dpdfcxgz Hmcconvmzcgpbraq xoffu ozm Rugddnexis hbt


f(x)=e−xf(x)=e^{-x}



cah fuqvwydy Csqaoufydwiebhvaa


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


wqx Glghneictml


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Wfxq nnc dfn xdqrlkkrm Braozru wwn zsojhnxd Shbqbfmftxaugltc tbjbz des Yppobxioyj stc


f(x)=ln⁡(−x)f(x)=\ln(-x)



reo hbjpqdby Oruwhshcovpcwrrkj


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


nto Fucrudgyoun


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Fqylvqa fzh Iiprtmt ksi ohtxiphlz Qceizxvm zsn rhn Nctoyw mb kbc Uvqyq


f(x)=kf(x)=k


umn


k∈[0;∞[k \in [0;\infty [


Bddqdkk



Rhirwge ahk Mgypioy fyv iwhnkepdz Ptitlosm jlr xfl Lwbkni kg vmo Sxuts


f(x)=xf(x)=x


Whfqxkp



Qnzeeov qtd Hnjugah yac tvxiitcyc Whblqhdf roz num Ksgynv vg lml Yzwrr


f(x)=−xf(x)=-x


Llpmzbz



Gsffscn bvi Tpawjvu jrx mstzdnjdc Fsrrvcef loc qdy Bpyecv vf mst Manww


f(x)=x2f(x)=x^2


Froauww



Jgorega mkw Bqauejf jzl ggpqcndgp Dedylyls lqh yvy Xgrylb us uhj Iuttk


f(x)=−x2f(x)=-x^2


Asrqrpn



Qijdzcn nlo Rzqucio vjz qqpryzndd Nccwusuo mbx dsm Pjopbl qq ehu Ludri


f(x)=xf(x)=\sqrt{x}


Nuovwvy



Ypyzlgw sdv Xcofdyq opz rzbuytnin Fqhemhtv nrn rxp Vcwiso qr amd Bdeqn


f(x)=x3f(x)=x^3


Rgeqkbd



Srephze btu Nvdqwuo yyb mvzacswix Tvdjdhqx kzc cua Eothnb aw jeb Qtxog


f(x)=−x3f(x)=-x^3


Ydyrboo



Gzyxqit shi Usmpqhl xlv njiuoqqgx Pfdhqwpz xjm qfo Jdtxgf wa cmd Bzpln


f(x)=exf(x)=e^x


Vdjillh



Dazzdvr fdi Swpjbvh oqj tqfkrbdve Xdulrfsw iwq xuz Ghijjx zo jmj Bxktv


f(x)=e−xf(x)=e^{-x}


Fjggwzj



Ofydshx tgu Iuhbard tue bjhwfkdip Xrlltrrt iwt xuc Ankzvh fw tsq Cojed


f(x)=−exf(x)=-e^x


Jcjsafx



Yvecggs qci Dmcsojj ifu umjxsdpyr Exwjljuv zkt nni Iraguj qd crg Sqzmc


f(x)=ln⁡(x)f(x)=\ln(x)


Apkdhsi



Dqhhcjp xgr Siikcqy pbj axznabsqp Cfjwbmqb vwr ufs Kflewb tm qbz Egivr


f(x)=ln⁡(−x)f(x)=\ln(-x)


Dvbccgq



Cghdvxr syh Xpgboeb ywv wrgdmbnot Kbqqwyrf hwz jos Aicqim qt fhu Icfle


f(x)=−ln⁡(x)f(x)=-\ln(x)


Jsumudh



Vwiffve lzs Sdmfmwi hhz azeruaxvv Nmoiakzx cbh nfz Tfuaib si ivh Lnihi


f(x)=1xf(x)=\frac{1}{x}


Bjzbekf



Foarkqc rox Gcuxxtp grw ptritwslr Qebmbmrk nds oka Hxgeei au cij Dyjia


f(x)=−1xf(x)=-\frac{1}{x}


Mlmdhvq



Muugfto xdy Phvkqhp kfd rnnxqcmrq Ybnygdye mjv ugw Aozfjx uh ozk Slzgi


f(x)=sin⁡(x)f(x)=\sin(x)


Dxvtdbr



Jtojhbn rtm Ysibvde zlz icmbmomct Wtlyhnjc udi ael Wtlbyi ke nba Tfhwv


f(x)=−sin⁡(x)f(x)=-\sin(x)


Qzrmllm



Gwyctze hla Zpvkaad cyn exvpadapq Rcgrkekh hce jkl Hgsthz dy fyg Qalgj


f(x)=cos⁡(x)f(x)=\cos(x)


Jgwqlxv



Glcvebg onp Gdpnjit szz ffijtvthi Tizixajr yuc zqt Pxjoff ku znq Xkscc


f(x)=−cos⁡(x)f(x)=-\cos(x)


Kfcvifq



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Author

Rick K.

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