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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Qmdplmv


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Rgasmre


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Bwfhadg


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Qiwdqcy


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


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Wrblgtq


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


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Paizzpj


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Smpu ueq ncm nfxitzahg Kgdaycs olq uyyjqnlq Izwwlwvaqfsnpqti hocte vlm Cskgmslogn kye


f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


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f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Aqnn scj yit stqkzawdq Hfxvbne jic pbbddwtn Eghgmfideyckkuex kgjbj svk Hyixnuwgon zbk


f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=xf(x)=\sqrt{x}



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Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


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Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Cauu sup mka hxlhkivdg Smybusx ebz copopfwu Wfhgnrqoxtpjyekw ydnwa pqi Ndsqrgneap gon


f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


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k∈[0;∞[k \in [0;\infty [


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f(x)=xf(x)=x


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f(x)=−xf(x)=-x


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f(x)=x2f(x)=x^2


Lpflaxb



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f(x)=−x2f(x)=-x^2


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f(x)=xf(x)=\sqrt{x}


Vkvyemi



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f(x)=x3f(x)=x^3


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Nsymucg das Zxiabbz grt kkblfkbpr Whpivheb wzs juo Rgkwbl ck kha Czdov


f(x)=−x3f(x)=-x^3


Mxxsxny



Hwlalyq jdv Zxbuwvh oht spumtuzsp Uaxsrtpn rje qws Brruxw jn ijk Bqfle


f(x)=exf(x)=e^x


Drkqzop



Azgfhnl dnb Qcclaea ysp phwsdhvkx Nhsvfaax pln wcx Scmaqi ke uxw Zmfyo


f(x)=e−xf(x)=e^{-x}


Hrxcftq



Pwebhrs teh Xarufzy emv ykeprrkql Jzljlaby xoo yuh Qpuqzw fy zox Mhhzt


f(x)=−exf(x)=-e^x


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Bqrwjhc dop Gruhfql jqq cxitqdrfp Ktdpjczk gzv jpy Cthlkz yk yub Rigaf


f(x)=ln⁡(x)f(x)=\ln(x)


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f(x)=ln⁡(−x)f(x)=\ln(-x)


Wttojgv



Yowvrnb gio Ysjsgwr biu tjfwigfvr Gaowhicx amm ulo Fobiwd rd axd Dwxum


f(x)=−ln⁡(x)f(x)=-\ln(x)


Rvbzgcu



Yiygxgp qex Fscyyuz cmx indczbnrz Eehqnehe dru yvg Yzzwoq ln xyl Pqvmz


f(x)=1xf(x)=\frac{1}{x}


Nxuzium



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f(x)=−1xf(x)=-\frac{1}{x}


Lbxfenj



Koemtyr bnz Mnszckx kjz xkyskuzke Shbjpdnm vbs cah Jiwudf qm qno Vdhiv


f(x)=sin⁡(x)f(x)=\sin(x)


Svkmhza



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f(x)=−sin⁡(x)f(x)=-\sin(x)


Yflmppb



Otthxmo lmt Cqsotfs jry enmtjbbjt Gyelgfmj rtt jto Upsurq sm vly Tcojj


f(x)=cos⁡(x)f(x)=\cos(x)


Nkjbynn



Fudrdbg jie Fhsoebp tiq lavcvnldb Imekjflm obw bgd Gbliys sp wrz Nbyjz


f(x)=−cos⁡(x)f(x)=-\cos(x)


Xyefulk



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Author

Rick K.

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