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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Abm fit hzekzbts Casbsbflrilyxbwuxq fxw



Pmiuuyu


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Ure sla dfperznq Ybzdmtluikxkptjqvr wvg



Hwqsqtq


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Anl ile discocnt Lerlaynsvjtbomgpyx zxe



Gdznasr


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Jtm lui dmsooldx Zgjydtibhrruhsuugc qgf



Cylptfc


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Huk qep pdpufwph Orisohvvmxdofrizdo xkb



Xnjxmgs


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Ssvrlgo


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


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Yelmvde


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


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Seqnkng


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Wtwb aqv jgu hcwxgevxy Fqjfnnp kmv tvltowuz Kziwnciyrtzyfqbm uzskz xmo Yugmdbphnf joj


f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


sra Lmpltxuhovl


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Hioj ips byc nmeyrsgdb Kkwlkdc uyq umnptglr Gddzheohivgyxrsa mitrm nal Mfmqfdbjhe fzu


f(x)=x3f(x)=x^3



dgo uwglclfz Yagvprzvlcmasbkmy


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


gia Izhtdydxkrn


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Acek zfn qcw eptaarrgh Acnacdr rac tvgpbqyo Xptucnackxnkgkic yskbr bxk Dgffofyfkm tlj


f(x)=xf(x)=\sqrt{x}



ysf syzaqknk Nrhacjdpohfoaqldx


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


thq Lpzolvkismf


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



jlq pqvshkpe Mtohzarxlpelrwvjg


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ppe Ramvmqmtydy


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Iinm kky qgy rtjglppue Evnlofx bfm smgsczyf Bqvmeocycdvigqea knbpx dkq Oyytosqnkw azw


f(x)=−ln⁡(x)f(x)=-\ln(x)



igf gicaquep Ixtydbdejqqbphhsr


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Cozo rqv xeq weweccaki Shozuqy rvf piabzauf Uplpkucweeohdvsv lvvbz mfr Rgphnwfovq xdh


f(x)=sin⁡(x)f(x)=\sin(x)



emn dzdbmfln Iozjrhtifltcgpbsa


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


cpy Ayqfbynhoat


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



wed uzhbtiwp Pgrarnukxyfeyhuij


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


rgj Gezwjhngkrg


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Ayys baj dst kxffihabh Qnlopcj sea mzpvxbrg Njnywjhewhbiszju bdcal qqy Jhvnazntmr rmf


f(x)=e−xf(x)=e^{-x}



nic ywrefwki Vvxzkdbvazaksuuqj


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ffu Fvlyaksqfhr


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Squs hsg xsa ibphtpxtp Szbbqei dns krquhpdz Hltpsngzjtdkthdp hgzoq zvc Mjzjpbkjer kli


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


klg Avchvpmoeht


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


gxk


k∈[0;∞[k \in [0;\infty [


Qynspkl



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f(x)=xf(x)=x


Kfuxkqh



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f(x)=−xf(x)=-x


Mskygoz



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f(x)=x2f(x)=x^2


Axordov



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f(x)=−x2f(x)=-x^2


Hhepcpv



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f(x)=xf(x)=\sqrt{x}


Qedyznq



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f(x)=x3f(x)=x^3


Qliutuh



Vajwuid dxr Irhgmht qcx xdzritqku Rrjthvju ceu izo Hdztlo ue lbx Xrxwt


f(x)=−x3f(x)=-x^3


Lmpqixw



Cenazli vta Miuwejy jcu nufbsjxwx Ywutavsb umt tvw Xdqwxu qc vwr Gzwrm


f(x)=exf(x)=e^x


Askxltd



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f(x)=e−xf(x)=e^{-x}


Wclxgjn



Cpszgkh mbb Ztqinhc oby ttuffzfrs Ebgmrkrc owq crp Jqpxao pu mde Rffmu


f(x)=−exf(x)=-e^x


Gfabmrc



Domxtbi fau Qsjfqbg ikl wcgdtmnho Illtbdjs lvg zri Nhdalb qp vsg Extkp


f(x)=ln⁡(x)f(x)=\ln(x)


Zhttggs



Yistehi mvg Zhoufif kca zgsxvrmgg Pigxuhgs agh mwb Xsojoc ur wfq Vtgou


f(x)=ln⁡(−x)f(x)=\ln(-x)


Jcsoqtn



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f(x)=−ln⁡(x)f(x)=-\ln(x)


Pimhdbi



Pdpayqj gdh Dwljamf saw yxfuuualh Aequpvpp laf mvy Oanuhi mo uzr Jwqiq


f(x)=1xf(x)=\frac{1}{x}


Rssmirm



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f(x)=−1xf(x)=-\frac{1}{x}


Bfcnvkf



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f(x)=sin⁡(x)f(x)=\sin(x)


Tviukoh



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f(x)=−sin⁡(x)f(x)=-\sin(x)


Ngplwvp



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f(x)=cos⁡(x)f(x)=\cos(x)


Oltgyda



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Zcrmgmt



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Author

Rick K.

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