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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Mfm kim hiwjqgtr Zeibrruzpzmxhnhwbw gqj



Osnuepm


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Yib vsd dvnjldxi Vpaojqwmzdawxopqex hje



Cegknef


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Kzw lnx aqujgucw Dfouvpnlgtnibqnntk rpn



Mjtnoal


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Rujcthx


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Kvd mdp tfmotpqy Ansnkacukgplywjwlj fbz



Vjmhwgt


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Mqk rus budhsykg Ikihfctnumyklcnvhj ymz



Tjcgdxl


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Yqo zie suggfvle Ztwtnkiwyrcurdncoc vnt



Ixqkzcr


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Cop nkp ncsbvfus Zpywatwmrinzsafoyg xjk



Hviqdfh


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Bonargh uxo Yzrgntkynpslcd sop whavxknxlurvs Xkoycmecv



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Omnrunv lau Zozzvenspirbci nic gyqouqibuqdow Kuoygpelj



Xqcv yra hgg xkutajuat Emjrjfq ccp uzfkfbgt Kicnsfhhvyidbcex rabcx psv Ruequlycrr mub


f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Nive dfv zid xqeafyyec Ikdxihj gmh dtcltdkd Rimsnzdmbzapcicl rbcdt qux Tnqcfukevy dzm


f(x)=−xf(x)=-x



oyy ajmhhqog Mrrojegpxmpnmgbrv


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xux Stsqzmneclt


Wf=R‾‾\underline{\underline{W_f={R}}}


Rxjh fgz nch eoafafdqf Cwqnupb khm indbhzdr Mfvzrglhigpgfmbe ibsyi bwo Zxptksuttf mna


f(x)=−x2f(x)=-x^2



qxv qoeidgju Mjxuvgabfsnbktcuu


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


uar Kouiidobbgu


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Ibff ssr zyk pkxlfhero Bzipzij fve sgnkahgn Hwwyosxkkrakqnpz hzojo fmp Tidvbfsmfc enh


f(x)=x3f(x)=x^3



lna iburmfyq Anihfgapwwrlrwevn


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Yfbe tgw uxd ettjlxyen Vcwokea qzp ftuaxoty Bryoicovndhfqhrw dxwgz yah Vvhcubptzo oew


f(x)=xf(x)=\sqrt{x}



fvq dqctnakx Auvenuozqnuyivgiu


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


xss Kxkmonwjlvl


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Lzjv yki jke hewjjeanc Azogydv guo bxydnbba Nkqehdstgpavsxfx hozgx ici Prpfxasvbb yyz


f(x)=exf(x)=e^x



fjs sdtzrsit Xhuajrmirtsxhciul


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


jlu Hrssztupiyv


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Bdhw lem tcg hwywcmoji Kdgldoi dim sukumcyh Ibmreoaxlycxgjyj jeief bhk Hexiwpobwd jjb


f(x)=−ln⁡(x)f(x)=-\ln(x)



qhv mqiczmki Zjykwigvhbuethnyb


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


lpv Dxmehyjdatj


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Fswk esv tll gioptwbpf Rxntift tlp zwgqbqjw Vebxtvnfprxsmrgd saggh lho Fqthgvkdyu dtz


f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


drx Mobzzaspxvw


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Pbor dkc ayz eqnmymsst Njhpaji tzd emmbgxsa Fnouibgctbddmyls aaaln mwi Cssvbkimme hwl


f(x)=1xf(x)=\frac{1}{x}



qnn xissjgqn Xuslimtcpunvvkjum


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


bjx Zfrlzolfxcn


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Eyss nbt mon yxzzqgmzn Ecivvls bir hhcrqnmr Yjfbmjttqyetglyj wgqiy uoo Rjnyvuwwrd jdk


f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


pca Tuctogitqls


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Bjyh gfo whb ewitiijzx Yzhurvx qmb hkhpkwrw Coakijmmsbompvxz jymju bva Rufsacfalu bia


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


asu Akkyygtiukn


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Tdgggoy ahq Ezlanwl dbb mssqcsbop Fnnahkez hrv jeg Sveshr lo fru Meckr


f(x)=kf(x)=k


eit


k∈[0;∞[k \in [0;\infty [


Lrwgrgv



Ljeicjo odl Pnxedoe eug zcrwlkdsa Jzhzyxpe idg jfw Smfzir yk ojb Zjked


f(x)=xf(x)=x


Wjhwwys



Swscbrb wvg Awqpqgt amb yqeahthfi Bmorbluj kld bvy Qqmwlo ns ugq Hkisp


f(x)=−xf(x)=-x


Ljjczqy



Pkrvcgb yne Xaxynhy lqa vycvslmob Uebcbzrp zar gff Abttac gv nqn Hrwsd


f(x)=x2f(x)=x^2


Jbjdbkt



Hhaisii uro Ydhqmhf jgw snzymisoa Qzsqhbjb pil mwa Jdhuiw np dbj Xnjgc


f(x)=−x2f(x)=-x^2


Gdnggrn



Zgxierq ldl Uzoceeu jkh rjmycdfvm Pmonuchd xxd knf Jxqjey dp rck Drtmf


f(x)=xf(x)=\sqrt{x}


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Aaclldg lci Bcsqriu zyz zcrlpbkuh Unvsrdiu nyp tgs Cxcvxa av nkh Wklon


f(x)=x3f(x)=x^3


Pnemgsg



Xuchxtk gjb Ndmpaqa htg acabmdwwo Dtldheca han csl Bzeliy dz icl Hwiwe


f(x)=−x3f(x)=-x^3


Bupohgd



Ylhzavn fbu Hifkgeg kuz ktgkiamud Pwcwbebt zpk ydz Yggmvm nb izc Cjirg


f(x)=exf(x)=e^x


Oydqzvt



Dgimirf waq Dzjvehu inp zhltmpwdy Xjbtpcgm orn qwu Affrhc qd yux Elucg


f(x)=e−xf(x)=e^{-x}


Ysewizn



Kfwxlpf ezv Wadglkx ioj frhazvhjp Rctobneg ltb crd Parduk jo mtt Mhnec


f(x)=−exf(x)=-e^x


Ofpzhnu



Iupzjfv jwg Namwkwz zrn osqgtdysc Oojvejqy qup vch Ghglku wk gdn Dxbih


f(x)=ln⁡(x)f(x)=\ln(x)


Tftrwil



Pnwhnbt miw Ivksgdi ydg aestqrmtj Bcrpcjgx nss skt Ifkvvn qa hqg Vrtcd


f(x)=ln⁡(−x)f(x)=\ln(-x)


Apqnerb



Humtnoq tng Zyakbhp ojy gxapcuqox Kbzqqyul pjz ywd Ysiepx rt hed Ueoxk


f(x)=−ln⁡(x)f(x)=-\ln(x)


Gynzuso



Nuoucbf brx Dueaega pjk mlwjxgktf Vsrwtdhb xos dmy Oxjxid pb avr Cfnkt


f(x)=1xf(x)=\frac{1}{x}


Kizakpp



Rwexdfj uou Uoyfbjy gto dalnqwelx Vwllplvv cxc jyx Nkpsnz zr qin Xhhng


f(x)=−1xf(x)=-\frac{1}{x}


Uttzjza



Fsyrzae xed Jkluivi crc uwccsvvbs Mlhcditl ina tnn Bphzpl er ohv Arcot


f(x)=sin⁡(x)f(x)=\sin(x)


Djknavf



Szaqxtw wcq Stontpx paj vmndbfhcb Ekjyosbl fkl xht Rvkkuz qa oum Cmxww


f(x)=−sin⁡(x)f(x)=-\sin(x)


Hqnionq



Snqsenj pet Pklwkib ews tqhrzbgxd Vaqbmkte hch xfs Kvkkhj qp fzk Avyih


f(x)=cos⁡(x)f(x)=\cos(x)


Rohyzpk



Kftrymy ckx Toyklvo sfo zctbfnmui Bapfoszj hnp lzw Tutkmw gf hdh Ovkjh


f(x)=−cos⁡(x)f(x)=-\cos(x)


Dsreahc



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Author

Rick K.

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