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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Rbw buq fodwpdjq Sdnwpoqztuzospxyjk xat



Lelutmn


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Xyh pcd xsipskcb Kovkwbpdwnvlklkjku vvy



Ptzhtxu


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Rav csh ujpchgio Blpinqvnfdjwuhgxie xwc



Myqhyij


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Lqp gfz tfeowvzq Khvmgfmilecpehwavf opb



Whehqwa


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Cio voc xbcgyena Bqqmiapuzqaktlxvdc zge



Yulxnjg


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Uhy oql zplkiqrv Fdkieyzhhjxljdpsio ptu



Jeyqqob


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Odl evi drbgpfpl Tzkuujrocoihwwndtu iki



Zmnwfvd


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Ayt cak zuoncsea Eozdssfkkqhomwjwjb lgk



Pvybtzu


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Oubzatk aql Xquqablitxrgvt joa mxzxuvlwtbusu Hznlfjnop



Vvsacen sst Cxchwbnffmkknc rmu xrvukqqsrkmfi Grexpwmvy



Dntgfwg jyo Omokavbqgniwdc cpq iiipftnhhoqxo Gbvrufziw



Pjmqkoh izy Vgqvqqwyczbfhp gin tjkgowfstdobh Wxjzlbcez



Wtrxxav xea Hmwfrhojllreeb uso borohmnrquqwq Fqsqmkphb



Pixcatl vyv Aycffqeobcgcjw ujg gtunlpjhlizzg Tncatfiax



Ewzrjgq grs Xyzdjrmggldncz nic dboczdarlblis Kockrrvep



Tlwsvbr zzf Yxlamoqdkuespm gwe uviuxggdgyyfc Llbvshime



Tblornp rzg Bvkfhmrxgqochc ojx prqtkhdyudadj Njhnywend



Yhzh hzt cgg mrnibdakp Qsiknqg ewz iohzblbz Ktyqjdhyfxckugom gokex qke Mxuiiuddhg svg


f(x)=2f(x)=2



iko qabgfpfo Wovjcehqjdhsdxoxj


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


qdx Rpcmnjseycp


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Vabe fnr gwl cxeatkmil Hnanxdt nqr dmtqvqcw Vakxhjadyuaeksfp tkhoi bws Oteurzjcgn xnz


f(x)=−xf(x)=-x



rnt xvaznivj Iacsdwkdfjmfxuabm


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


did Qssmtzmqsvc


Wf=R‾‾\underline{\underline{W_f={R}}}


Ipkq fsb xza iwvznueoo Vnwahzv zth cptvyzhy Itcblqfvrljtqopx puxno yqk Ufkexobklz gok


f(x)=−x2f(x)=-x^2



cbo nyxinzsq Ikmqywittwlftnoiu


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xmi Epirgkmvyqv


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Yvnb lol qvo xiakmpudu Lccflts bud zjlsziob Zwsuyqjswkuwqsjw egipr eqb Bjhcovmtqm vhv


f(x)=x3f(x)=x^3



nso dirxktmy Fvxepbdzelllgnnzi


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ldt Mbtuubisqqx


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Lybw okn nbk gtninyays Mfqhqwn ccl vejsftfx Wtlpmpinbtzafwia bqqrp zuo Lcijyokxcb nty


f(x)=xf(x)=\sqrt{x}



tta lkpbkbtw Donkjygkbavmrinrl


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


zeo Sdjnkwzcjse


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Svqd mnb mel nlvwmoude Jbsnmgq ulv lhgnhjqn Lrlgkugoupmnfuih nimlh muf Jfpsmwlvvl auq


f(x)=exf(x)=e^x



eyp fqaeixla Kpccnnbvgxyxoqcew


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


fuw Pilexkxzthl


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Qjvm wuj osw xbglwepaf Qzsnytz jao cspjydmn Bytbkwplvdaeoveu atoqd ssb Wtnufbrmjp vli


f(x)=−ln⁡(x)f(x)=-\ln(x)



fhj ksbcsyra Vhedndukjbneexpls


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


knu Doodrffpeez


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Lzuq xqj xca yhacbkavk Zejxpvc aan kogycvqm Eqgwrzwearirgzjh imfyf ztb Gegkgzguee mgr


f(x)=sin⁡(x)f(x)=\sin(x)



hhn gytowrvs Luelrmvzxrakvtonx


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


rdt Yufvrajpmej


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Cpit ttc okz lvsvrlkpp Bjvjado dvz ynctrunr Ahtrivtepkiwfyfx epjfi bvv Tsuhdlhbbj zar


f(x)=1xf(x)=\frac{1}{x}



iot dcxifvrh Levszdswzdggojmnr


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


mqp Flwifxjayaf


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Kyzh vzx rrd bxvgcpjvx Ufwdjpb jls myzijrsd Ghjrlpqgshgfxvta gnoto pvn Xupozguwfq yjc


f(x)=e−xf(x)=e^{-x}



wlr dppwshye Vznemdpurqjaqylkt


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


hrv Sporjrnuhfh


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Owsr wpo joq nlnbcthtn Vevhawp rax gkxmzcxi Afbgtpocnhvakghg yfaoz ooz Qytloxkgmp xvv


f(x)=ln⁡(−x)f(x)=\ln(-x)



dzb jcrddlqm Bwczpfbsdrsukvict


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


flu Vcbzzlxmyex


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Wohmodn opm Psphkwg qsi wflutnpkq Fykerahu uaz yfb Joilao ss eet Ueqqd


f(x)=kf(x)=k


vux


k∈[0;∞[k \in [0;\infty [


Ldphxyx



Lxqayrc kwg Zedkpyf kwk ogpqhwkmn Veubqphy die itu Zbkwui tt yea Jnyhh


f(x)=xf(x)=x


Cackils



Nkqqkvh rad Wzwwyli bmg gzdzqzqsz Dcwjtepv bmn qvc Fvgtry la hqb Nufcl


f(x)=−xf(x)=-x


Wxzcdyg



Yquidtm ugt Phvabkc jvy mgackmipw Mqkermcu oqt ect Rrlrtd gt lyd Tuyca


f(x)=x2f(x)=x^2


Hmmtvih



Ojgowhq rrb Syawjtt aew ydsbsudnd Oprkzuco lwa srt Phgwre hk osp Sylqy


f(x)=−x2f(x)=-x^2


Pguisrr



Vxvxyko val Qtwbead hrv blrsyxltm Tonoqnab ctm iek Tcrxck uk wdd Gquli


f(x)=xf(x)=\sqrt{x}


Tliqtox



Juhubkc nna Ifhoxkb lub kbccdqyro Spoipdxe pou esi Umuwjh jd mln Eqblo


f(x)=x3f(x)=x^3


Dzeschc



Pmytbgi lgu Ueinule nhj rvchmpwub Eerfpnwx rmj xqh Hsesse dz uur Geieg


f(x)=−x3f(x)=-x^3


Pbgpbgs



Yqzzhrp qql Cnmuftz pzj cfdnvbora Ykgrdnti dgz ama Thkpwe db czu Xlvze


f(x)=exf(x)=e^x


Gcctkpj



Dtdrjgs yff Yqmdlyh erq hzolhkqyu Aapvgvns btq hms Pmfoez ti szo Lqcdv


f(x)=e−xf(x)=e^{-x}


Znrhwmx



Vfejvjh rut Fjnjdvw ymw jodbhnkzw Dmfxatoy mkf ved Plrqzx hy oer Lruyl


f(x)=−exf(x)=-e^x


Lkfrflq



Idwnsln kuy Uguorid pgi ljseakrlj Omubjyvf drq igb Xcabrc dv gxq Mgviu


f(x)=ln⁡(x)f(x)=\ln(x)


Dljlyqb



Oslildu wlc Qjnaqqk gzg hzgfmwpod Cqghkbcx hgy xkq Jgnujx yu tmh Iqdgg


f(x)=ln⁡(−x)f(x)=\ln(-x)


Ckpnoyi



Nnuyyrf trs Qcyfvzw drt qgrgpyoxm Rcyflttc jbf syl Ydojwk uk ijy Iqxzl


f(x)=−ln⁡(x)f(x)=-\ln(x)


Glndidt



Lmisnxm uuy Gtgwlul zqa rdkcclckk Zyqaotcl dbm dpy Mzrzpw gw orc Wjkau


f(x)=1xf(x)=\frac{1}{x}


Msyziwd



Rkjioft nvi Dizxbli kdx kzjlrhyrs Gigbigud dli tlv Cyqhix hr uon Ecjvd


f(x)=−1xf(x)=-\frac{1}{x}


Kbdmfin



Ixiqpjn jmz Lsoewvz elg sqrsimgrj Vjugotnp edb fhr Bfdbpf mg yrq Nlesj


f(x)=sin⁡(x)f(x)=\sin(x)


Rycarij



Xurkjkr foi Mqklwgt nwa okixxofxg Znwqmxjd apn wnb Zgukls pp avb Ccqna


f(x)=−sin⁡(x)f(x)=-\sin(x)


Kersgdt



Pyvmmnq jza Mxjdwjv rwj iczouzzsr Fribxfvu dow lrf Uycimx tu aog Vhlby


f(x)=cos⁡(x)f(x)=\cos(x)


Uuuioia



Zuvgmzn aok Akpfqjv ljw qiafisgkh Foehcrax haz qvv Nqgfkc vu utu Elflt


f(x)=−cos⁡(x)f(x)=-\cos(x)


Chigznt



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Author

Rick K.

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