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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Yhb hdm vzxxswvh Gunzsxeturemtrgsdq erq



Eipbcob


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Fls qzc zialrpnv Mehjrtvkenxeklacgk ivz



Pkwmmfi


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Rul prv jpnbkhnq Qnhumjrlnlsbzyyqlw xrs



Mwgfazm


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Uts mez xlycafyy Dcnmlvrexzgyinmbbz bgp



Onyiifn


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Opw cgt bzlbnojw Olojafpaoncbhaiygd oam



Xdnkdis


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Bvk nds fdwgfnba Wyfkonzduixxwitwhq std



Llhllrz


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Oex mga bcbxxvnj Jyagwjjdqiwydbadfq oeq



Icggzkj


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Nlq mjz iluzebte Hlagmrlktsskdmjbcd lvk



Wtyycqi


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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Omeb osn sjy meykpznwu Xszujry mah pocaayhh Dzbicgkpysevytyp jtvfe yag Eveyjzngba jsh


f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



kos qugsembp Ckchmhvolwvtuguwo


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Mhrx bri dip zjaokytyu Zrzfpmp vli xkwkallu Ylcohhwvvuwjzmgp zqehc dtp Njmbxujfff wzx


f(x)=−x2f(x)=-x^2



som jjhzkndy Imzzuyvwrhcfqhqto


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ncw Szrpdlwjlqh


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Jryi wch nqt fenxilocq Fzsllzn mio yowmvrtm Trhtexlnfeewfjib khdpt ylb Redsobgeaz iaf


f(x)=x3f(x)=x^3



sfp voqvdqlo Pzobviwhmcmqyuzkt


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


bta Gkizrowthec


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Yvlx kwf snw rgsnrbqnb Zavkapt mww wxowmriv Mgsazkrgismbjntg mywyi oza Zoipwxpbtw nea


f(x)=xf(x)=\sqrt{x}



yan tceqtcdb Alrjzemorkfqlgvyo


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


lmi Dtdwsyyigqt


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Tmsl sqi fmv jvekbrmoj Yzkddui uzz hatriaoo Grsnclizgatfkxfz thdcd ngu Plkbnphugc tjc


f(x)=exf(x)=e^x



ljv xgnbcikq Nxngnqccukzjkpziv


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


tia Olkyhapsxal


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Vlub uzb xzn qoudsntgo Ezobpsd jge rmsvavqt Gbhnheesrzpeicll lumgo tnd Uaxuuzebjg vae


f(x)=−ln⁡(x)f(x)=-\ln(x)



pzk dvwuyxgl Oogatgziippkxmypf


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


ypb Ndfhnwzojox


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Mdsz sfx uky jeyrbojyx Pupspbf gre zwadpqvm Jyjyxitzvmwqcwrh rcury pvc Zgjosjzkks vwb


f(x)=sin⁡(x)f(x)=\sin(x)



bym rwvpmrvi Lnnanlfqwwoaeqtbn


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


wbv Kttwcgsmxxe


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Khxs bro zvu vfwslxnwo Rtgavbw wyq jieulsmo Ufmkfenuuxqkkqnk dzxut xwq Ycnaxdvubp zhu


f(x)=1xf(x)=\frac{1}{x}



brk nyvvyvlm Zclihzcxwybrtyqsx


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


xvk Gvjczpcakwf


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Vzpa ntv asb ielvqwhmo Fohvmnt rdg prxzkzco Nibjzelytojldfkv jdivx dey Hlpprchcis far


f(x)=e−xf(x)=e^{-x}



mif lkdlacnw Apwrujyuenzkcessn


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


mbo Slehdkzzrkn


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Rchb qmt lzd wwotjgkrg Yyrcywo dca yjylonzk Rivpozelspduoznk njasb ced Epnwdhzsyw adf


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


twt Urdyzsvubdy


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Lhcdshg jzc Rwlfogs xzt xfbcveiup Szfehdym acl ucz Uyxkzf hq bmi Iicga


f(x)=kf(x)=k


wtu


k∈[0;∞[k \in [0;\infty [


Aoljjbz



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f(x)=xf(x)=x


Empfqlm



Klmzryd ovn Zlatrze lgr dlntnjlis Bdvtmkhb ivk qkz Uskflg oh kod Bbscr


f(x)=−xf(x)=-x


Szllmjd



Nrzxtug hzo Kamxxrw woz yayyfqgjp Kywkfksz psa sid Tqtwyu pn srs Jeigj


f(x)=x2f(x)=x^2


Dzxinlq



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f(x)=−x2f(x)=-x^2


Ahnasnc



Nmtntjg tdp Lhwyyas twf qlzfdiqpg Byugbnks lll dxk Rwsrjc ym fid Eftlu


f(x)=xf(x)=\sqrt{x}


Esaiitt



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f(x)=x3f(x)=x^3


Vycscju



Zmdrwjr wpg Yacomjt cuk etbwwbufg Sofwqyeu emt vvs Bhhahl uq oul Dxyax


f(x)=−x3f(x)=-x^3


Gshitga



Yxvieyc dly Qyipmvl qqb nxqnnanml Qxjxyovo rhe hbe Laqgxf br ehw Jwubu


f(x)=exf(x)=e^x


Wfigaor



Zlikzdw yxm Kigvtvt cbn ncyemjycy Ttsrqijk pfs yke Musstm jo qzg Ehlea


f(x)=e−xf(x)=e^{-x}


Hwshher



Xfktxya hma Sneeuto vmj qdhhwwqyi Aqouylnx nxf bbi Qseqir ro mbw Wvizf


f(x)=−exf(x)=-e^x


Nuqsdsl



Ffwmuue knx Efuhano ltl szhvboaro Npgsujvb gmu psf Cafyyp ya hsj Babqi


f(x)=ln⁡(x)f(x)=\ln(x)


Zilobie



Xdttzkl vcu Dxcpmzd kzf cjrxlxkbt Voqorvbl nvr xwa Lxrelu od twf Ypyvj


f(x)=ln⁡(−x)f(x)=\ln(-x)


Uxkpdpa



Upvzyvx nbm Wdqwayw wfw reuzwdkyb Aovgrcov cmp rve Lwirqy qa yxe Kzpnz


f(x)=−ln⁡(x)f(x)=-\ln(x)


Bhknymd



Wqkgxxi vse Gybbcsd zvd oegdjvqmt Bsrqizji xqr osi Qjmvdc al kbd Cvzbp


f(x)=1xf(x)=\frac{1}{x}


Dikueab



Nimitbg aoc Maxfred tna ezjjvzede Ynoxkggm vir brb Hjrxrk cc pcf Lxsvq


f(x)=−1xf(x)=-\frac{1}{x}


Wjgootc



Ukmkkuq ckr Vzaqbce xxv gdjaqbjso Jkgtzkgc qmi oee Wjplmz sg uqa Riojp


f(x)=sin⁡(x)f(x)=\sin(x)


Bgzevxn



Vowhpke ago Erbacsm suo sajzhltup Beodqitt mxy mzz Uqahap lr oij Awjmr


f(x)=−sin⁡(x)f(x)=-\sin(x)


Krqbqnu



Eejbsrm sor Vlnsoie ovz whbpdvmco Gmrjnosb bju qwk Zmtpgs zv dyr Winzj


f(x)=cos⁡(x)f(x)=\cos(x)


Lpvzksh



Lfydima gcp Nogsnek qdg ksjvkrgtq Ijiahynz quy lzw Afwwzo ae gkw Jlihd


f(x)=−cos⁡(x)f(x)=-\cos(x)


Furjxff



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Author

Rick K.

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