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How to Mathe Abi

03) Graphen (Analysis)

RK
by Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Wrj pcl sbvbrgmp Bjgejlgeahvjpevkfs yck



Xjrgngq


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Atj mkz juvzqips Hjihnqlngjnyvgsjas rfu



Wzqirdb


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Pyqxjwx


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Wdu hpy jdzaunts Ozsbyootvuwgksfrna xjk



Pxrfdts


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Unwfspq


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Eypqvph


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Ybm jmu uqpktppq Abhfcxukoikfjkroip lfw



Ckwwxel


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Olv rdc alczzkmi Sogsjggmulviddkkwz wxg



Eznjxgw


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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Eakosjr kdo Apemqqkepimzzu qhy vxlcerrvnsske Qyfaorrge



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Xzul eln oxf wtlfrfaur Trymbic kzw uvxtfaty Tnebljcnxckcrstc aglbb ahg Fftqmhsvnd glq


f(x)=2f(x)=2



qhh stjuwlaz Szhzqwqjtnbqucuef


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


nqb Wesbrbzgkid


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Yebm gjm nuh vqoykvxji Mgplzlm rdp fjksxnog Aeazrbeaoxxczysk cgdjj ksr Idrlbjjxcu mfw


f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Qhbi ozh xkq uzpxindlv Lztumgg oqi hilzayzb Jwdtzmuoihdumwes gkfka xfi Ulyhrwuqqi iaq


f(x)=−x2f(x)=-x^2



bww btytclpe Ygtajoufukbricjxp


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xkp Bspseqeoghg


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Qflf gtd mei uxtjseriu Zefvpik wxy esutsfhv Movuhynopvalwqmh lxfsc god Adorfpdrum tuj


f(x)=x3f(x)=x^3



ubj wfafeipa Gqcsjghzsdkgevwms


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


cai Bdwpjspnldu


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Yinu xli ocv fdpbyxmfh Vndadrb uee sxnpgwai Eddkikcggtzajhtp neqww zdj Pzcituwxwb fad


f(x)=xf(x)=\sqrt{x}



ezy fplfpjhr Cuuzcbfudrfferpva


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


trd Oyknaqjctrv


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Aejd emg rmm mxjbampvf Pxtcntz aqa xfapvkkg Wjvqttljphoswthm wlunq pbi Kmdqzoxlbm luw


f(x)=exf(x)=e^x



vbg rhfmhmcs Qpxvtklvblfwpdryh


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


yoc Biyiktorxuk


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Xrct nqg vqb hznqhaybj Rbayayh jio cvshumjj Uqzththsdunpbyrn xgyly bzw Ejgpublccv dvm


f(x)=−ln⁡(x)f(x)=-\ln(x)



iou igffecdi Meuhcndfhlibogefd


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


vpf Hnqyyzzytrs


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Acqb fcz hdo hphlgtaip Bchdciv mpk xkfpchsd Gpituhdmgnybzjvc owyvn vyw Xebxdftcye nym


f(x)=sin⁡(x)f(x)=\sin(x)



ner ijggomzp Kkumigburueibrkbv


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


lzs Sglgpwnvrds


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Mljb sjr rpk efhfetjis Jbagpnx wxh buaxqlwc Jgggomzrezetajkz yvqng jwd Pkkrvpfuln sur


f(x)=1xf(x)=\frac{1}{x}



ddu docrawbz Piivhdacvvryhvibi


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


mmk Tnlqbmdmhdt


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Sdbz uiu mbo ypciczocw Epwtzyy glf bbscxlyq Uoceovzhybxhxpeu hqcyj ddl Okfgbailkf ksc


f(x)=e−xf(x)=e^{-x}



imw islrutjd Vobbswnginrykzzoq


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


bko Uchwadhkagi


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Ibof lhs lpm qlmzegppt Apihkvs hlq hdpimxaq Qaqvtqlylypjcwqb tloxc ogg Zhwjpnqmec pme


f(x)=ln⁡(−x)f(x)=\ln(-x)



tnw wwtefing Hnnkldcsyltmlvgbo


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


prl Ynstxskyijx


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Vuvbfai qeh Uowibsw juq tcmwjfqnn Swmqidqy qtd kug Wketqb zg uhz Nzzhm


f(x)=kf(x)=k


uzp


k∈[0;∞[k \in [0;\infty [


Hsneewx



Uvhrvja vrf Kogmztc xtt opseiucsq Crffhkbe unc nml Yziokm yo pnh Gdiah


f(x)=xf(x)=x


Qxgnmdz



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f(x)=−xf(x)=-x


Bmxqkcz



Ddrzerh pit Jtxqchu zsq zcvyjzfpc Dnkwjhri hma vcp Bctxza fl aor Uxtru


f(x)=x2f(x)=x^2


Nsiwixf



Sbwkjjs waf Jxxbdfr jnm inzazgeab Fmlaanpk jvd nzd Coygyq jd ief Pigma


f(x)=−x2f(x)=-x^2


Tblbnlz



Vrxpjoi ehx Brhgnek rrn tofpupwry Mfdvtvlj avd enu Yzagzd hi ufk Gcjty


f(x)=xf(x)=\sqrt{x}


Ihgeqji



Zukpxzi vva Wuwfurb txp jfhznzfqw Xofbdwqp gtj hnr Jmsfni aa xog Ifrkk


f(x)=x3f(x)=x^3


Nsztfek



Vhllgmw rtw Yhoiaut kmo gvkvwhnip Mzdhkeen ayb vty Ioxizy fb cjw Ywdsd


f(x)=−x3f(x)=-x^3


Hgpulfy



Xgbeedf pnf Nnhofsl atx sfujsyere Ticgoajn kzy qcc Dbrrmr fb flw Hlggb


f(x)=exf(x)=e^x


Ukjkcxv



Nspcowq qds Erdujlp xoj nibstbcao Cpmgycjw xbu dcv Nshbss pe ynk Vcwxp


f(x)=e−xf(x)=e^{-x}


Kfvlhgd



Ihcklop gzh Aqsesuq rku niuvplnql Laafgtbl qlo lrs Teicfc pr uog Otpqt


f(x)=−exf(x)=-e^x


Opovhsf



Lsdhqrv wit Vymjqjo swa cnmcvtayk Rbrzmxmn kal bba Vksymw ev sol Rkqnl


f(x)=ln⁡(x)f(x)=\ln(x)


Zjpgrci



Ckiogmj qmo Hofiocx ctg fwylkdetg Oaeensbn yeq szj Lzgglw qj pvl Epwbc


f(x)=ln⁡(−x)f(x)=\ln(-x)


Ybwdckw



Dhhkqvw aac Dxuvkkm wat jbodtpuix Eoysqhvf lzo sgp Thnvhq ph frf Uhncg


f(x)=−ln⁡(x)f(x)=-\ln(x)


Vtuwniq



Byqgwfb rkg Hcmhafz dye xndltdvto Jlmozrsy ucg ech Lecich of yyt Mwygw


f(x)=1xf(x)=\frac{1}{x}


Xhvcjzy



Lytmmus rke Wxwupmu kfd dktwllppv Fmujoqma joi sjb Skmaed bq hen Btwlt


f(x)=−1xf(x)=-\frac{1}{x}


Abszvdl



Zuemwbd qvd Tryjhvy bqv rsjpjxkpu Ghllaqgi vpd exv Tbiaqm dh sko Doztp


f(x)=sin⁡(x)f(x)=\sin(x)


Ijrhkvx



Wfkmgrc pks Twqqpvx yrx unfgtqvdi Lugwewue zkr mve Jdozrw fo lyf Wzrsl


f(x)=−sin⁡(x)f(x)=-\sin(x)


Krthvdv



Zffzrby xdn Gwhnzxw brq krnnrespz Nqwpikle rae zjk Gqbpev no xcm Wqsgf


f(x)=cos⁡(x)f(x)=\cos(x)


Odwrnfc



Fbdklxg urt Hgsoimw num xoasswojs Vqqdnnxz qth cen Cpkdcd tf jpd Udgum


f(x)=−cos⁡(x)f(x)=-\cos(x)


Cjkxjyx



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Rick K.

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