How to use chain rule to solve this equation:
y= (1+3x) ^ 2
y = u^2 u = 1 + 3x
dy/du = 2u du/dx = 3
dy/dx = dy/du * du/dx
How to use product rule to solve this equation:
y = x * sin2x
y = u * v
u = x v = sin 2x
du/dx = 1 dv/dx = 2cos2x
dy/dx = (u * dv/dx) + (v * du/dx)
How to use the quotient rule to solve this equation?
y = ln x / x
y = u / v
u = ln x v = x
( v du/dx - u dv/dx ) / v^2
How to use implicit differentiation
when differentiating y; add dy/dx next to it
e.g.
3y^2
= 6y * dy/dx
Last changed4 months ago