when comparing recombination rates, we always observe:
a) uniform recombination rates across different chromosomes
b) higher recombination rates in femals compared to males
c) A direct relationship between physical and genetic map length
none is correct
->
a) varies widely
b) not uniformal
c) not strictly direct or linear
Thomas Hunt Morgan and colleagues spent many years crossing wildtype and mutant fruit flies. If Morgan crossed a female fruit fly homozygous recessive at two linked loci controlling color and wing length (i.e. bb / vgvg), to a male fly heterozygous at both these loci (i.e. +b / +vg), what distribution of offspring genotypes is possible?
0 heterozygotes
-> only female fruit flies recombine -> no recombination here with bb/vgvg
In the figure the star represents a recent mutation at a gene locus. The letters represent other loci. Which other locus is most likely to be in linkage disequilibrium with the mutation (all else being equal; assume a sexually reproducing organism)?
C
-> I guess closest ?
Which of the following statements about quantitative traits is not correct?
Quantitave traits vary continuously
Quantitative traits are normally determined by multiple alleles at multiple loci
Qunatitative traits are not affected by the environment
Quantiative traits can be affected by drift
Quatitative traits can be affected by natural selection
Quantitave traits are not affected by the environment
Why are permutation tests commonly employed in QTL mapping studies? Choose the best answer
To estimate effect size of identified QTLs accuretly
To determine the staistical significance of QTLs as it allows us to correct for multiple testing
To identify candidate genes associated with QTLs
To directly manipulate the phenotypes of individuals in the mapping population
to improve the resolution of QTL mapping by introducing additional genetic variation
To determine statistical significance of QTLs as it allows us to correct for mutiple testing
Dobzhansky-Muller incompabilities (DMIs) …
… can explain how hybrid sterility can arise
What mechanisms may contribute to maintaining associations between traits involved in prezygotic isolation and those under divergent selection? Choose the best answer
Random mating and genetic drift
Physical linking, inversions, or pleitropy
Hardy-Weinberg eqilibrium
Homologous recombination
Phenotypic plasticity
Physical linking, inversions or pleitropy
A very determined student is interested in two discrete traits, fore-wing color (black vs white) and hind-wing color (also black vs white), that vary across populations in a species of moth (where there is no recombination during egg production). Previously she studied these two traits independently, and has determined that: • Fore-wing color is controlled by a single locus (with two alleles), and that the black fore-wing allele is dominant over the white fore-wing allele, and • Hind-wing color is also controlled by a single locus (with two alleles), and that the black hind-wing allele is dominant over the white hind-wing allele. She now wants to consider these two traits together. F1 Generation all black fore and hind wings F2 200 offspring, 97 black black, 103 white white.' What is the conclusion?
a) that hind and forewing colour are pleiotropic effects of the same allele
b) that hind and forewing color are controlled by loci on the same chromosome
c) that hind an forewing color are controlled by loci on the Z (sex) chromosome
d) that hind and forewing colour are controlled by loci 48.5 cM apart
b)
A very determined student is interested in two discrete traits, fore-wing color (black vs white) and hind-wing color (also black vs white), that vary across populations in a species of moth (where there is no recombination during egg production). Previously she studied these two traits independently, and has determined that: • Fore-wing color is controlled by a single locus (with two alleles), and that the black fore-wing allele is dominant over the white fore-wing allele, and • Hind-wing color is also controlled by a single locus (with two alleles), and that the black hind-wing allele is dominant over the white hind-wing allele.
F1: Ff Bb
Pop A: FF BB
Pop B: ff bb
second experiment:
In a second experiment she decides to additionally look at a third trait: Host plant
preference. Females from population A lay their eggs on the leaves of apple trees,
where as females from population B lay their eggs on the leaves of orange trees.
A literature search tells her that differences in host plant preference in this species are
genetically determined and are controlled by a single locus with two alleles, which are
co-dominant. In other words, heterozygote females have no preference.
She confirms this by assaying host preference in female offspring from her F1 cross
and finds that each of these hybrid females lays roughly equal numbers of eggs on
orange and apple leaves.
To look further at the genetics of host preference she mates a male from her F1 generation
to a female from population B. She assays a large number of female offspring from this
cross:
• 465 females with white fore-wings only lay eggs on orange leaves
• 585 females with black fore-wings lay on both apple and orange leaves
• 102 females with white fore-wings lay eggs on both apple and orange leaves
• 98 females with black fore-wings only lay eggs on orange leaves
Based on these data what is the genetic distance between the locus controlling fore-wing
colour and host preference?
Male: Ff PR
Female: ff RR
Offspring:
465 ff RR
585 Ff PR
102 ff PR
98 Ff RR
genetic distance (recombinant divided by all)
102 + 98 / 465 + 585 + 102 + 98 = 0.16
-> 16cM distance
Question 3
Your Uncle is a chicken enthusiast. He has recently acquired a small group of rare
Andalusian chickens. The Andalusian breed is unusual in that some individuals display a
distinctive slateblue plumage. This blue plumage of the Andalusian is caused by a
‘dilution gene’, which, in combination with a gene for black plumage, produces partial
dilution of the melanin, which normally gives the black colour. However, not all
Andalusians are blue:
• birds with two copies of the dilution allele (AA) have near total dilution à white
• birds with no copies of the dilution allele (aa) have no dilution, and are black
• birds with one copy of the dilution allele (Aa) have partial dilution, and are blue
Tending to his new flock, your uncle notices that one of his Andalusian females (which has
black plumage) is laying beautiful blue eggs. After a little reading, he suspects that the
blue eggs are the result of a mutation normally found in the Chilean chicken breed, the
Araucana. Egg colour is determined by maternal genotype
• Blue eggs are caused by a recessive allele b
à bb females produce blue coloured eggs
• Bb or BB females produce normal white eggs
i) Your uncle decides to mate a blue (plumage) male with this black (plumage) female
which lays blue eggs. He raises the first 20 eggs and finds among the offspring four
types of female phenotype combinations exist:
• Blue plumage and lay white eggs
• blue plumage and lay blue eggs
• black plumage and lay white eggs
• black plumage and lay blue eggs
From this information we can determine that the genotype of the father is:
A) AABB
B) Aabb
C) AaBb
D) aabb
c) AaBb
Since both bb and Bb must be present and mother is bb -> Bb, with BB bb not possible
Plumage colour is just one aspect of plumage. Assuming there are 6 diallelic loci
that influence plumage (size, shape, colour etc), how many possible 2n gamete
combinations (haplotypes) can be formed?
A) 12
B) 36
C) 64
D) 2080
2080
-> 2^6-1 * (2^6 + 1)
in what measure is recombination rate measured ? And what does it determine?
crossovers per megabyte (mB) and determines the genetic map length in (cM)
-> relates directly to genetic map length
In a linear regression plot, how can the h2 (narrow sense heritability) be derived?
the slope of the linear regression gives h2
(parent and offspring environment must be unrelated)
Last changed2 months ago