Buffl

Richard Merrill

AS
by Anton S.

A very determined student is interested in two discrete traits, fore-wing color (black vs white) and hind-wing color (also black vs white), that vary across populations in a species of moth (where there is no recombination during egg production). Previously she studied these two traits independently, and has determined that: • Fore-wing color is controlled by a single locus (with two alleles), and that the black fore-wing allele is dominant over the white fore-wing allele, and • Hind-wing color is also controlled by a single locus (with two alleles), and that the black hind-wing allele is dominant over the white hind-wing allele.

F1: Ff Bb

Pop A: FF BB

Pop B: ff bb

second experiment:

In a second experiment she decides to additionally look at a third trait: Host plant

preference. Females from population A lay their eggs on the leaves of apple trees,

where as females from population B lay their eggs on the leaves of orange trees.

A literature search tells her that differences in host plant preference in this species are

genetically determined and are controlled by a single locus with two alleles, which are

co-dominant. In other words, heterozygote females have no preference.

She confirms this by assaying host preference in female offspring from her F1 cross

and finds that each of these hybrid females lays roughly equal numbers of eggs on

orange and apple leaves.

To look further at the genetics of host preference she mates a male from her F1 generation

to a female from population B. She assays a large number of female offspring from this

cross:

• 465 females with white fore-wings only lay eggs on orange leaves

• 585 females with black fore-wings lay on both apple and orange leaves

• 102 females with white fore-wings lay eggs on both apple and orange leaves

• 98 females with black fore-wings only lay eggs on orange leaves

Based on these data what is the genetic distance between the locus controlling fore-wing

colour and host preference?

Male: Ff PR

Female: ff RR

Offspring:

  • 465 ff RR

  • 585 Ff PR

  • 102 ff PR

  • 98 Ff RR

genetic distance (recombinant divided by all)

102 + 98 / 465 + 585 + 102 + 98 = 0.16

-> 16cM distance

Question 3

Your Uncle is a chicken enthusiast. He has recently acquired a small group of rare

Andalusian chickens. The Andalusian breed is unusual in that some individuals display a

distinctive slateblue plumage. This blue plumage of the Andalusian is caused by a

‘dilution gene’, which, in combination with a gene for black plumage, produces partial

dilution of the melanin, which normally gives the black colour. However, not all

Andalusians are blue:

• birds with two copies of the dilution allele (AA) have near total dilution à white

• birds with no copies of the dilution allele (aa) have no dilution, and are black

• birds with one copy of the dilution allele (Aa) have partial dilution, and are blue

Tending to his new flock, your uncle notices that one of his Andalusian females (which has

black plumage) is laying beautiful blue eggs. After a little reading, he suspects that the

blue eggs are the result of a mutation normally found in the Chilean chicken breed, the

Araucana. Egg colour is determined by maternal genotype

• Blue eggs are caused by a recessive allele b

à bb females produce blue coloured eggs

• Bb or BB females produce normal white eggs

i) Your uncle decides to mate a blue (plumage) male with this black (plumage) female

which lays blue eggs. He raises the first 20 eggs and finds among the offspring four

types of female phenotype combinations exist:

• Blue plumage and lay white eggs

• blue plumage and lay blue eggs

• black plumage and lay white eggs

• black plumage and lay blue eggs

From this information we can determine that the genotype of the father is:

A) AABB

B) Aabb

C) AaBb

D) aabb

c) AaBb


Since both bb and Bb must be present and mother is bb -> Bb, with BB bb not possible

Author

Anton S.

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