carbonyl

b

wolf kisshner does its work and then in basic medium, alyl halide undergoes E2

Cant be clemmenson as it includes acidic medium which would break cyclic acetal

ans is b

b

Tollens works on hemiacetals but not acetals

Al releases e- which form Ketyl anion

The radical goes on the 2 degree carbon

two such ketyls combine to form b

in the trimethyl orthoformate, h+ attacks the oxygens and forms ch3oh and +ve charge on C. then water attacks and we get an OH on the C

This repeats 3 times till we get 3ch3oh and c with 3 OH bonds which gets dehydrated to form formic acid

the ch3oh then react with the cyclic compound to form (b)

b

b as clemmenson mei H+ can attack the S and rhe O and break the ether bonds

HNO3 breaks the ring and form dicarboxylix (adipic acid) which after Caoh2 releases co3

ring contraction occurs and we get c

Methanal undergoes EAS on benzene as H+ attacks the o and makes the Carbon extra electron hungry

Agno2 reduces ald and adds NO2

c

When the peroxide link breaks, Oh- gets removed and so we’re left with O+.

to deal with this, the ring breaks and carbon gets -ve charge which then forms db with O

The carbocation formed gets attacked by water to get primary alc

b

Phenyl group always looks to stabilise the thing its attached to. so it can both take e- and give e-

in this case it gives e- and so hence ans is b

c

KH attacks on the alpha carbons as there, the -ve charge will be stable by reso

Then CH3I attacks and Ch3 gets attatched

Since everything is in excess, this repeats twice

A

b

this is because lower steric hinderance means greater nucleophilicty

c

Kmno4 oxidises and then h2o opens the diol

Aldehyde is formed in B

The leftmost N of the reagent attacks the aldehyde as its the most basic as it doesnt resonate and lose its electrons to the oxygen

hence ans is a

gives positive iodoform

has a carbonly group as its being removed by NaHSo3

hence ans is b

A

1. form ald

2. attack on ald

3. gives H+ to remove the grig ka doosra part

4. turns ester to acod

5. The secondary alc attacks on anhydride

grig forms and attacks on methanal

the acid both removes the grig and hydrolyses the acetal

ans is c

then hydrolyse the imine (just remove the db N and get an O in its place)

hence ans is b

b

Ald>keto

you can make the order yourself now

Beckman rearrangement forms amide

ans is b

b