Whats the definition of molecular biology?
the branch of biology that deals with the structure and function of the macromolecules (e.g. proteins and nucleic acids) essential of life
How long is one helical turn (B-turn)?
34 Å, (3,4 nm)
10,5 base pairs
what are the three processes for information transfer?
Central dogma
Replication
Transcription
Translation
DNA -> RNA -> Protein
How “wide” ist the double helix of DNA (B-form)
2
0 Å (2 nm)
How big is the major and the minor groove in the DNA double helix (B-Form)?
Minor groove: 12 Å (1,2 nm)
Major groove: 22 Å (2,2 nm)
What is the distance between two basepairs in the helical strucure of DNA (B-Form)?
0.34 nm (3,4 Å)
How are nucleotides formed?
By condensation reactions of
phosporic acid
2’-deoxyribose
base
React to form dAMP (nucleotide)
Which bases are purines?
Adenine & guanine
What are the components of a nucleotide?
Base + deoxyribose + phosphate
Which bases are pyrimidines?
Cytosine, thymine
What stabilizes the DNA double helix?
Hydrogen bonds + base-stacking interactions
What is the structure of Adenine?
Adenine is a purine Base
What is the structure and the name of the Adenine Nucleoside
2’-deoxyadenosine
What is the structure and the name of the Adenine Nucleotide
2’-deoxyadenosine 5’-phosphate
What are the Preferred tautomeric forms of bases?
In DNA, adenine and cytosine prefer the amino form, while guanine and thymine prefer the keto form. Rare imino or enol tautomers cause mispairing and base-substitution mutations.
also: Tautomerie depens on the pH-value (changes charge distribution)
What is base flipping in DNA, and why is it important?
Base flipping is the process in which a single nucleotide base is rotated out of the double helix, allowing enzymes to access it directly.
It is essential for DNA repair (base excision repair), methylation, demethylation, and recognition of damaged or modified bases.
What are syn- and anti-conformations of nucleosides, and how do purines vs. pyrimidines differ?
Definition: Nucleosides can rotate around the glycosidic bond, placing the base either above the sugar (syn) or away from the sugar (anti).
syn-conformation:
Base sits over the ribose sugar.
Much more common in purines (A, G) due to their larger double-ring structure.
Can occur in left-handed Z-DNA (purines in syn).
anti-conformation:
Base extends away from the ribose.
Default conformation in right-handed B-DNA (all bases anti).
Pyrimidines (C, T) almost exclusively anti because their C2-oxygen causes steric hindrance that prevents rotation into syn.
Biological relevance:
syn/anti patterns influence DNA helix geometry, Z-DNA formation, and base recognition.
What is the difference between right-handed and left-handed DNA?
Right-handed DNA (B-DNA, A-DNA) twists clockwise and is the normal DNA form, with all bases in anti-conformation.
Left-handed DNA (Z-DNA) twists counterclockwise, has a zig-zag backbone, and contains purines in syn- and pyrimidines in anti-conformation.
What are 3 different forms of DNA and how do they differ?
Property
A
B
Z
Proportions
short & broad
thin
thinner
Rise per bp
2,3 Å
3,32 Å
3,8 Å
Helix diameter
25,5 Å
23,7 Å
18,4 Å
Helix rotation
Right-handed
right-handed
left-handed
Repeating unit
1 bp
2 bp
Bp per turn
11
10,4
12
Glycosidic bond
anti
anti-syn
Notes
RNA-DNA-Duplex
Normal DNA
Alternating pur-pyr
DNA is generally in B-form
RNA-DNA duplexes assume A-form
Z-form forms alternating purine-pyrimidine sequences and is promotes by high salt, specific base modifications (i.e. methylation) and negative supercoiling
What is the propeller twist in right-handed dsDNA and why is it important?
Base pairs in B-DNA are not planar; the two bases are twisted against each other like propeller blades.
This propeller twist enhances helix stability by improving base stacking, reducing water accessibility, and compensating for the weaker A–T pairs.
Which base-type only adopts the anti-conformation and why?
pyrimidines have an oxygen at the C2-position
The C2 oxygen atom produces significant hinderance to the rotation of the glycosidic bond between pyrimidine and ribose
What is the nucleoid in bacteria?
The nucleoid is the compact, organized region of the bacterial cell containing the chromosome. It lacks a membrane but has a highly structured DNA organization.
How is the bacterial chromosome organized?
It is arranged into negatively supercoiled looped domains, stabilized by nucleoid-associated proteins (NAPs) such as H-NS and Fis.
H-NS: histone-like nucleoid-structuring protein
Fis: factor for inversion stimulation
What changes occur in the prokaryotic chromosome between exponential and stationary phase?
Exponential phase:
many looped, highly supercoiled domains, numerous transcription factories.
Stationary phase:
fewer loops, relaxed DNA, reduced transcriptional activity.
Function of H-NS and Fis?
H-NS binds widely across the genome, helps compact the chromosome, and often represses transcription of many genes.
Fis binds to AT-rich consensus sequences, bends DNA, and regulates transcription, replication, and recombination. Levels peak in exponential growth and drop in stationary phase.
What are transcription factories in bacteria?
Clusters of strongly transcribed genes (especially rRNA operons) with high concentrations of RNA polymerase and nucleoid-associated proteins (NAPs) such as H-NS and Fis, forming superstructures in exponential growth.
What is the role of topoisomerases in managing DNA supercoiling?
Topoisomerases relieve DNA supercoiling by introducing controlled single-strand (Type I) or double-strand (Type II) breaks and resealing them.
This prevents DNA tangling and is essential for replication, transcription, and chromosome segregation.
What are SMC proteins and what is their general function?
SMC (Structural Maintenance of Chromosomes) proteins are ATPases with long coiled-coil arms.
They mediate chromosome condensation, DNA organization, and higher-order chromatin structure in bacteria and eukaryotes. (Examples: condensin, cohesin.)
How does ATP binding affect SMC proteins?
ATP binding triggers SMC dimerization, bringing two coiled-coil arms together.
ATP hydrolysis promotes closing and locking of the SMC ring around DNA, enabling chromosome condensation.
What is the structural organization of an SMC monomer?
An SMC monomer contains:
a conserved N-terminal ATP-binding cassette (ABC)
a C-terminal ATPase domain (Walker motifs)
two long coiled-coil domains
a central hinge domain that allows dimerization
How does an SMC dimer interact with DNA?
An SMC dimer embraces two DNA segments, forming a large protein ring.
This allows tethering of distant DNA regions and creation of looped domains, essential for chromosome compaction.
DNA binding stimulates ATP hydrolysis which triggers condensation.
Also:
Interaction between two SMC dimers generate ring with even larger diameter
ATP-induces polymerisation of SMC leads to lare nucleo-rotein complexes
How big is the human genome?
3.000.000 kB, 20.000-25.000 Genes
DNA length: 2 km
What are the levels of human chromosome packing?
Double helix (2 nm)
Pearlchain chromatin (11 nm)
Chromatin fiber (nucleosomes, 30 nm)
Part of chromosome (despiraled, 300 nm)
Part of chromosome (condensed, 700 nm)
Complete chromosome (1400 nm)
Structure of human chromosomes?
“Metachromosomes” (State during metaphase, max. condensation)
two chromatids, linked by centromere
Centromere: Region between two chromatides
Telomere: single stranded ends of chromosome with short sequence repeats
What type of replication usually happens in cells?
Semiconservative replication
After replication each newly synthesized double helix is a combination of one old (or original) and one new DNA strand
3 Steps:
Initiation -> Elongation -> Termination
What are telomeres and what is the Telomerase?
Telomers are protective caps at the end of chromosomes
maintain chromosomal stability and prevent chromosomal degradation
they are regions of repetetive DNA which prevent “copy loss” of the ends of chromosomes
After many cell cycles (division, replication) telomeres are getting shorter -> cell is aging
Telomerase: Enzyme; Ribonucleoprotein
reverse transcriptase where RNA is used as matrix, priming the 3’-OH-End of G+T rich telomere strands
prevents telomer shortening
What repeats are generated by telomerases?
3000x TTAGGG
Which two enzymes bind to DNA before the replication fork?
Helicase
dissociates H-H bonds between base pairs
Topoisomerase
Removes supercoils
Afterwards: singe strand binding proteins (SSB)
prevent re-annealing of the DNA strands and stabilize the single-stranded DNA that is exposed after helicase unwinds the double helix.
What is the function and composition of the oriC region in E. coli?
oriC is the chromosomal origin of replication in E. coli. It contains conserved sequence motifs essential for initiation:
Three 13-bp AT-rich repeats (unwinding region)
Four 9-bp DnaA-boxes (binding of DnaA) At least nine proteins cooperate to initiate replication at oriC.
What is the role of the four 9-bp sequences (DnaA boxes) in oriC?
The 9-bp repeats are DnaA-binding sites (consensus TTATCCACA).
Cooperative DnaA binding bends the DNA and initiates opening of the adjacent 13-bp AT-rich region.
What is the role of the 13-bp repeats in oriC?
The three AT-rich 13-bp sequences form the DNA-unwinding element (DUE). (Consensus: GATCTNTTNTTTT)
Because AT pairs have only two H-bonds, DnaA can easily melt this region to open the helix and begin replication
What proteins are required to initiate replication in E. coli?
Protein
Function
DnaA protein
recognizes origin sequence, opens duplex at specific sites in origin
DnaB protein (helicase)
unwinds DNA
DnaC protein
required for DnaB binding at origin
HU
Histonlike protein, DNA bending protein; stimulates initiation
Primase (DnaG protein)
Synthesized RNA primers
Single-stranded DNA-binding protein (SSB)
binds ss DNA
RNA polymerase
faciliates DnaA activity
DNA gyrase (DNA Topoisomerase II)
relieves torsional strain generated by DNA unwinding
Dam methylase
Methylates (5’)GATC sequences at oriC
9 proteins
What is the 2nd step of Replication and what happens during that step?
Elongation (Initiation -> Elongation -> Termination)
Leading strand synthesis
DNA-Polymerase III synthesizes DNA continously in 5’3’, starting from the primer
Lagging strand synthesis
discontinously as short fragments (Okazaki, 100-1000 bp)
Primer replacement
DNA polymerase I removes RNA primers and replaces them with DNA using its 5′→3′ exonuclease activity
Sealing nicks with DNA Ligase
What is the first step in replication and what happens during that step?
The first step ist the Initiation.
Steps:
Origin recognition
Replication starts at a specific Sequence (e.g. OriC in E coli) where initiator proteins (DnaA) binds to unwind.
Complex of 20 DnaA molecules binds to the 4-9 bp repeats
recognition of A/T rich sequences in the 13 bp repeats requires ATP and the HU protein
Loading of helicase
DnaB Helicase (aided by DnaC) is loaded onto the ss by the primosome.
Hexamers of the helicase DnaB binds with the help of DnaC to the separated DNA strands and separates more DNA
Primase recruitment
Primase (DnaG) synthesizes short RNA primers complementary to the ss to provide 3’-OH group for DNA polymerases to begin synthesis
ss-stabilization
ss-binding proteins (SSB) bind to ss-DNA to prevent re-annealing and protect from nucleases
What is the primosome and what is its function?
The primosome is the DnaB helicase–primase (DnaG) complex at the replication fork.
DnaB unwinds the DNA; primase synthesizes RNA primers for Okazaki fragments.The primosome drives lagging-strand initiation and coordinates discontinuous DNA synthesis.
How do type I and type II topoisomerases work?
Type I Topoisomerase
makes a nick in one strand of a DNA molecule, passes the intact strand through the nick and reseals the gap using energy from ADP
-> reversible & energy efficient
tyrosine at the active site, covalently attaches to a DNA phosphate, thereby breaking a phosphodiester linkage in one strand
the two ends of the DNA double helix can then rotate relative to each other, relieving the accumulated strain
the original phosphodiester bond energy is stored in the phosphotyrosine linkage, making the reaction reversible
Type II Topoisomerases
makes a double-stranded break in the double helix, creating a gate through which a second segment of the helix is passed.
Name an example for a helicase and describe its structure
Bacterial monomer helicase PcrA
Consists of 4 domains:
A1: binds ATP (P-loop)
A2
B1 binds ssDNA (together with A1)
B2
How does the Elongation of DNA work?
A single matrix strand is required as a template
Primer with a 3’OH group is required
DNA elongation occurs when the 3'-OH group of the growing DNA strand performs a nucleophilic attack on the α-phosphate of an incoming dNTP.
This forms a new phosphodiester bond and releases pyrophosphate (PPi).
PPi = pyrophosphate, which consists of two linked phosphate groups. PPi is immediately hydrolyzed into 2 Pi (inorganic phosphates), making the reaction irreversible and driving DNA synthesis forward.
Why is the lagging strand synthesized discontinuously?
Its template runs 5′→3′ toward the fork, so Pol III must synthesize away from the fork.
As the fork opens, primase must repeatedly add RNA primers, producing Okazaki fragments.
The leading strand can be synthesized continously,because its template runs 3′→5′ toward the replication fork, allowing Pol III to extend the new strand 5′→3′ in the same direction as fork movement without interruption.
How is DNA polymerase III arranged in the replisome during replication?
Pol III functions as a dimer, synthesizing both leading and lagging strands simultaneously. The τ-subunits link the two Pol III cores and connect them to:
DnaB helicase
the β-clamp
This coordination enables continuous leading-strand synthesis and repeated cycling on the lagging strand for Okazaki fragments.
4 β-subunits per enzyme form two ring clamps
What are the core structural components of DNA polymerase III?
Pol III is a holoenzyme with 18 subunits, forming an asymetric dimer.
These 3 form the core polymerase:
α-subunit: polymerase activity (5′→3′ synthesis)
epsilon ε-subunit: 3′→5′ exonuclease → proofreading
theta θ-subunit: stabilizes the ε-subunit
Additionally:
4 beta-subunits per enzyme form two ring clamps
2 beta-subunits form 12 symetric helices (-> ring)
How does proofreading during elongation work?
DNA polymerase III proofreads using the 3′→5′ exonuclease activity of its ε-subunit.
A mispaired nucleotide destabilizes the interaction with the template strand, causing the newly synthesized DNA to shift from the polymerase active site to the exonuclease site.
The ε-subunit cleaves the incorrect nucleotide, and the α-subunit then resumes correct 5′→3′ DNA synthesis.
How high is the processitivity of the DNA-Pol III and why? (maybe unnötig)
50.000 nucleotides / min polymerized (high)
Beta clam form a ring around the DNA, increasing processitivity by preventing the enzyme from dissociating during enlongation
How does DNA polymerase III achieve high accuracy during replication?
Binding of the correct complementary dNTP induces a conformational change in the “finger” domain of DNA polymerase III, forming a tight binding pocket in which only A–T or G–C pairs fit.
This increases selectivity and reduces misincorporation.
Combined with proofreading, Pol III inserts only 1 wrong nucleotide in 10⁹–10¹⁰ bp.
Since the E. coli genome is 4.6 × 10⁶ bp, this corresponds to one error every 1,000–10,000 replication cycles.
General:
Purine+Purine -> too wide
Pyrimide + Pyrimidine -> too tight
How are RNA primers eliminated during DNA replication?
DNA polymerase I removes RNA/DNA primers using its 5′→3′ exonuclease activity (“nick translation”).
It cleaves nucleotides ahead of the nick while simultaneously synthesizing DNA with its 5′→3′ polymerase activity.
As Pol I degrades the RNA primer, it fills the gap with DNA.
When Pol I leaves a final nick, DNA ligase seals it.
Comparison of different DNA Polymerases in E. coli
Pol I
Pol II
Pol III
structural Gene
polA
polB
polC (dnaE)
subunits
1
≥4
≥10
5’3’ Exonuclease
Yes
No
3’5’ Exonuclease (proofreading)
How are two okazaki-fragments joined?
by ligase activity
A phosphodiester bond is formed between 3`-OH of one DNA fragment and the 5´phosphate of the next.
This reaction requires energy: ATP in eukaryotes and archaea, NAD+ in bacteria.
Explain the ligase reaction (e.g. joining okazaki-fragments)
Adenylation
Ligase enzyme reacts with ATP/NAD+, becoming covalently bound to AMP
Activitation
AMP is transferred to 5’-phosphate of DNA at the nick
Nick sealing (by AMP displacement)
3’-OH attacks activated 5’-phosphate, releasing AMP and sealing backbone
DNA-Ligase can not join two ssDNA molecules. It repairs single strand breaks
in dsDNA.
How is replication terminated in E. coli?
Replication ends at the termination region, which contains multiple Ter sites (each ~20 bp).
Ter sites are binding sites for the Tus protein, that blocks DnaB helicase upon binding.
This creates two “fork traps” that stop clockwise and counterclockwise replication forks exactly within the termination zone.
How is it ensured that the two replication forks do not meet/overrun each other?
Tus binds to Ter sequences and acts as a one-way barrier for helicase movement.
From one direction, DnaB can displace Tus; from the opposite direction, Tus locks onto the DNA and halts the fork.
This ensures that the two replication forks meet in a controlled region rather than overrunning each other:
it creates a Clockwise and a counter-clockwise fork trap.
After termination, how are the two daughter chromosomes separated?
The duplicated circular chromosomes become catenanes (interlinked rings).
These are resolved by Topoisomerase IV, a type II topoisomerase that cuts both strands, passes one duplex through, and reseals it.
This decatenation allows the two daughter chromosomes to segregate.
Last changeda month ago