Alkyl halide

it wont give because the carbon is chiral

so sn1 will give racemic products

but sn2 will undergo inversion

hence products will be different

D

Assertion to direct hi hai

Reason is true because excess ethanol mei solvolysis hogi which is always sn1

2>4>3>1

2 is obv because of stability of transition state

4>3 as bromine is a better leaving group than chlorine

1 is last because the 3 degree carbon in the vicinity still asserts steric hinderance and thus slows down sn2

Usually not, it should favour subc more in primary and secodnary halides

but it does show elimination when reacted with teritiary halides because of the stable carbocation