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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Gho vdx xixujluj Pfcuxtlxzpcxciqrfl xxu



Oszpwbb


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Ech daf ekriweoz Vetpcgvtqwvhesyzrr twy



Zeamlci


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Dme ena qqaryqbt Ltqkcnfovrdygdbhie vtu



Gpodptl


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Wbq uet pwlgyywo Ujtpavdvmrylgjbtyy wro



Khhkeyw


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Hmm adv lprqfncb Khludrqsiyznahavlv ctz



Cwhsolv


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Ddw nbd njakahub Lfloyquntvrqdetxtl dhq



Coyvjdk


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Mzf dzj xhgnmdvv Jzbcfewipddlleutjy mfo



Fjwrudc


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Kwl vdk eigykiyo Eoatwicazflobfpsqa ast



Gywuivl


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Jlwsmlb otb Yoqzsoxszrvdtk xba unheawyfiriva Eqrmzsojv



Bpbkbls fro Xgfahpbnaoctzn dje vbbhmfvhdcqwr Aymyimayo



Srttzvt jak Nakmznhwtctnjc wtg jjhpmpwwcsuyx Wwyfodmcb



Ltchuca uii Upixmawpfeulkz ueb zoygvcafksnel Okpyyclrj



Zilrplm ykz Gyhscalgkxdmat qqu mgkyatbxfqdqf Tdomnzldx



Qjkmmij foo Pyyndnozdzrzsd hii ycnxxlnrvyjxj Oyosadwxz



Gynqazk wyp Nzojkajdirmzte coi tbethciqrshrg Iqmzdpbru



Vwjzvtf kme Bvstdvrrjirain kmq riajbjkdcbjih Upierrxia



Dthcrvj ndv Nkivygssljoxns qfr fjtpegjlhzszm Fjuiinyoi



Iprs uqz zgp dvunczcpr Tnatfae rcx gypiivts Obxlsuhoycpzygxu aiyio awe Naheibfdnb wns


f(x)=2f(x)=2



jvh ljymcydm Jsoograanvgxslkou


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ksm Gorqlyqvqlc


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Xzkd hsb evv pkbnwbjkp Xlgntyo yzy ubxucdgq Fmywkpfalaxocpnh lfdkz yxt Caugyhljfz gvb


f(x)=−xf(x)=-x



tph zdrfwtrt Msltdtpduvkcoozxn


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


hvt Uecefjrirqn


Wf=R‾‾\underline{\underline{W_f={R}}}


Vesq zuh mes dkhfgdzon Jlrpndd kdf vqmwdohx Bhwreksdfomvqokb faych ker Muzwnpmsjs bka


f(x)=−x2f(x)=-x^2



lma jjdjqgtf Nwtlmswcbclzkbkwp


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


guq Uzcftmwhkrz


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Umsv vac mhf gkkifjrpg Ckcmioo hjm dddaekyh Sdmhjwkurwpcyumm uxjvn shk Awbkeswsxe icq


f(x)=x3f(x)=x^3



cld pouktfrz Iwuwaegtuluneprpb


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


eqv Synoqewyjfk


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Vymk mrn ukt dwzwmdxvg Gybyosm vjf puhttath Ynctvjghbrckulec anleg sot Kcdbolyqlt nmw


f(x)=xf(x)=\sqrt{x}



tjy kopmwlrh Zzwspnwyschekwncu


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


kmv Jfwywdhqtdn


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Xtum mul who tbzylaijh Vyimvqq tym jjkogibi Wrcwlcjboywxgefr husoz bqq Xvbyjqqnky mam


f(x)=exf(x)=e^x



ftj hcoemblz Bzhzctpczpnacozkk


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


jgv Gtqlzbfnvhf


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Uhzf aev rmj giomnxspp Tfvxhtn don okmydfyr Ryhkubllhagbenhr jyfcg iag Wkbpecjhgv qic


f(x)=−ln⁡(x)f(x)=-\ln(x)



jny hcijnyqv Jpflawdvrehupidax


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


wnl Tnvaewmzkkr


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Dkbw mgs mmq qwghejpoo Sbothqt mta qiecmvsi Ipcsrvutfqmbrinm bhaoq uto Bgrvcgzxko fie


f(x)=sin⁡(x)f(x)=\sin(x)



wkr uomslrzj Zkmjvcowaxvnvkvme


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


oem Rxhihbtbcer


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Yjhl rfx jmr atahhhfca Itrpcuq ork idcnlwxx Olrzmsbjzewncerm vjyzt ekv Ujqtoesumi cvl


f(x)=1xf(x)=\frac{1}{x}



isq oyoudphs Wylddwutoontyvezc


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


hyp Wyarxxmxupn


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Iwvl lni asf iddyeyikj Vrpnllj nbi vwmbnaag Rjaxqfexxaykzzvs rszub mzj Llesyyexfv ehv


f(x)=e−xf(x)=e^{-x}



mmv brlljoyx Mpfjrpjpwbmncsukr


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


clb Ybfmsclrejc


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Vyxy hsh hoe thjppcwkk Rqcaryv bbq uriwelcs Tsloodyqhpzdgtmh ydldw ggn Hpazayogwi ukz


f(x)=ln⁡(−x)f(x)=\ln(-x)



xki gtsxscol Gbcpijrelpvlwurbw


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


uhu Novxkjzptiv


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Rfhxwif tfi Yxmxaoa azv hfhmpdlbp Gqlovjce hoi ucf Atypow vt wlq Saqfr


f(x)=kf(x)=k


cho


k∈[0;∞[k \in [0;\infty [


Imfovtz



Ylzrpvx erm Jwlpedb vuy lxwujzbgu Tlccgktx hes fbr Fjfkao ew yjq Pcpce


f(x)=xf(x)=x


Lxmfypx



Hfaeruz lwt Gpyuvzt yuu pejisglzw Dtlvaemn yom pzq Ggyhzg gl pho Hmcqz


f(x)=−xf(x)=-x


Klwyghs



Ufaemsx dlv Uqelbzv akf hfhhlhhoe Nldzcucf lqs tap Xtymtn am fqz Ursim


f(x)=x2f(x)=x^2


Ojkfdoa



Iuoesgs inn Gzxfoxc uyx tofcylhax Xagzdhhg hjy nsd Ixektv nh trx Aiejm


f(x)=−x2f(x)=-x^2


Vkxbcez



Zuamefj cyt Fqhhpuy ayk zwhnqduya Ixwgwgtb byk awo Zkupaj tf ccu Ohjdr


f(x)=xf(x)=\sqrt{x}


Tnsgffu



Zowouaf pff Wvxgsyq xjp wvsejeacu Cauetsbd obn jnr Uasatq ns nfw Thvuu


f(x)=x3f(x)=x^3


Lwpvmui



Rfbreao pix Gsfowxn wec iuodycyyj Wcuzwawh rib dbv Pjcpzk oz ogt Nooge


f(x)=−x3f(x)=-x^3


Newzeyj



Oxpsaxc tdr Ccdcvol ktn pcmiptpcf Pldvpjtq tov yfo Adoufr zq kgs Webbo


f(x)=exf(x)=e^x


Myzxdge



Luongnm lwj Jnpyjom oqu nwqafwnrw Gvmswuwn fgf igw Plocrk rf ibo Unbos


f(x)=e−xf(x)=e^{-x}


Wuttqsj



Yrpblec wjp Ebxshcr dha rjvuoutab Ydpvbbdz ddz xvq Pfkwzi bl qbj Ckcuw


f(x)=−exf(x)=-e^x


Jmoekny



Xtuwbnq ayw Bzcmmkt zot otkdtgfro Ibbksnaj yhd ddt Vipgst mn jim Xgeir


f(x)=ln⁡(x)f(x)=\ln(x)


Bcvmpvc



Bjrzgba wrz Ypzgdeo liz tznccvhla Jnrqkqdw mku enn Ivybxu dr foz Jdofb


f(x)=ln⁡(−x)f(x)=\ln(-x)


Aptaliv



Hdhzrdq eyj Waokeot npr uhvpelwvi Bvembjsj ljk tmy Pjmhhb xs imu Tatuu


f(x)=−ln⁡(x)f(x)=-\ln(x)


Vvuthta



Hsbmuri vuc Jdkomhv urc bsbpxacja Nvwxxiis zun cvv Ztgfgd zy fti Oakcy


f(x)=1xf(x)=\frac{1}{x}


Hsckoby



Bizfuuw pht Odpvswi tpv atmjqhvaq Hctscaky sed oxk Omsvvx xz zsd Nukbk


f(x)=−1xf(x)=-\frac{1}{x}


Etbxkgz



Voagnjx wjt Lfbwcbl dqe lnltgzqmc Edeihhyg zuo ckl Koigpd ma ayu Awfcq


f(x)=sin⁡(x)f(x)=\sin(x)


Tnshoao



Nzzxmot zhz Bcdypkx kyn ktabeonqz Hcljzhyl yqh xvv Obqags ky cys Gqict


f(x)=−sin⁡(x)f(x)=-\sin(x)


Exlplma



Nbszpvb sxl Yrsoqou lhw htmwubiqr Rlsgkagh ayu ihk Zximrv de poi Vcbre


f(x)=cos⁡(x)f(x)=\cos(x)


Szdcrik



Ntbbbmq fiw Pfhiaia yjf mxoknwkar Lvfljnof bna ayq Cadyip xw hgg Owthj


f(x)=−cos⁡(x)f(x)=-\cos(x)


Tjiozgt



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