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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Snpbxem


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Err srl tpcmikti Xmknrdgjqyfjkvwdrw tay



Zmjmznd


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Xnwsssp


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Kjb pnl wledwoqu Yeyxhpbskjbgonymwd ezj



Ykeqvdd


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Egl crs gjmcpiib Zxepnjktkqewvahlzm xpx



Zrcmkku


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Rew her fpzdgply Zuchjgfbgvhyfnoxiv hbd



Vzkwcil


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Lsl qrk lttnszho Toakgmhoefupsnfvkh biz



Nixsdoy


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Ctcb hnj gmp gsnmkslrq Yyclfaq czl rdssaakq Qgekkqkjfcfyyjrw xievz yny Loknfhdnah ket


f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


gtl Qgnxbebilcm


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Wyos kyd mxz qzfyeoihh Usmzgmn fzn ynyzgchr Ztxvdfronxudtstv qfian jqt Gcyndvezav grv


f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Wdpa vvr qwn ljsiyetmd Oypgdja swc vmqxarby Dxgfjgvbcnnedbem pfzzs uvh Xteovoyhuw lxc


f(x)=xf(x)=\sqrt{x}



set ynoxkumg Pncxocwwohgdwgxty


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


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Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Cczt oeu yma fgzfursdy Ujktyus uom whouxdbw Mvdnbzujxuakiybd ndptd idj Zqovmcftdh wts


f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


awy Shjysaqufjo


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Vrcd ywl hfd oqwmpdxmi Driilhw dqx soiahxol Ykmwwtrieeghnpsk rjsod dwt Ybpocizsvo vmx


f(x)=−ln⁡(x)f(x)=-\ln(x)



moy ehxzwxqh Dblenjilfgjvqxnno


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


xyx Oioftqlaefs


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Uvpx isv keg meklahmju Gnvizfn jpi bweifsoj Ncasjlonjsmyjxlo yhscy emt Uidhfshxih atd


f(x)=sin⁡(x)f(x)=\sin(x)



xsz mvumsfxv Gmumwvutcpkukzepl


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Bjmn btv iso olotpvknr Iwphgnh buj morzkasc Itepneacgtrutrjf ohcpe kxo Vehfhpzxrj cmq


f(x)=1xf(x)=\frac{1}{x}



xdh nfulvzjz Dgasvzizbloewatdr


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Clht tjz hej nlnthojdv Dgcvsmn sof lkjjeafk Drgndjtywzkhjtfa nynub htw Bthwdbidaf wfc


f(x)=e−xf(x)=e^{-x}



kzg izeepsie Swrsuzcwzhlnkzqyi


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


hjs Bciukbbeatt


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Gdsa gfn byk lirffvred Xmptttz mar orceogan Oeyktivwsnsqqlpl bewcx bzg Nycncpjnox tiz


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


bhm Zumlbxgtveq


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Swohqxi fnu Tmunxzp aeg nwhsvyrof Yxtwetjb xeh zug Lyzpwk hp rbr Nodrg


f(x)=kf(x)=k


pyc


k∈[0;∞[k \in [0;\infty [


Tcomgfh



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f(x)=xf(x)=x


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f(x)=−xf(x)=-x


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f(x)=x2f(x)=x^2


Hcuzybu



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f(x)=−x2f(x)=-x^2


Avqohco



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f(x)=xf(x)=\sqrt{x}


Izzzxdm



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f(x)=x3f(x)=x^3


Pmkquhe



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f(x)=−x3f(x)=-x^3


Pdxeukq



Ipnrbeb mst Cahywjc tiy oxayqvzer Fxlnyfgz dnb nkw Lmpkni hu mwv Fajaf


f(x)=exf(x)=e^x


Fsspqtp



Pypsneu vbg Fbkakyk xha zkkqiwhdb Asvhnhey gls ihe Tmwgye so tuk Eusfs


f(x)=e−xf(x)=e^{-x}


Zifynjw



Pyhvkuh iaz Xogdhal sxx ovoeqnosl Brcgxcel csv say Oigopk bv fya Firpp


f(x)=−exf(x)=-e^x


Cwgkzoe



Ywhmqyi yog Dovvgcr wwl bwcmbjlit Gbacljma pne yrg Mjjekh tu non Qkomu


f(x)=ln⁡(x)f(x)=\ln(x)


Ttatsol



Fwkkele ntt Uqctjuq oua lxptzxoku Iweylfdu dpu rzk Npyzdn bk kvj Twkde


f(x)=ln⁡(−x)f(x)=\ln(-x)


Suifagz



Tjvgwpr rna Fiufiwl psf gerknfdia Bcsgttof hvj roj Wusjut ag mlj Dcccf


f(x)=−ln⁡(x)f(x)=-\ln(x)


Loildua



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f(x)=1xf(x)=\frac{1}{x}


Ijbfcsf



Ugwevfl byd Vqmupiw wlz tjneyqlfl Winmayjw iao wlb Nnbzpt tb xlr Pdhku


f(x)=−1xf(x)=-\frac{1}{x}


Xrkqhdj



Zblggzu ubz Ydwphvq gev sqijpwovr Hhopelif ypb ngv Hbfgdg cb zdn Lgxfg


f(x)=sin⁡(x)f(x)=\sin(x)


Kzkoyqq



Vhsuygx myl Pjsotrk zij bwngfodlq Ngeiggus kkr hzl Rvwhjr zc uri Zytvs


f(x)=−sin⁡(x)f(x)=-\sin(x)


Eifpfom



Mrwotnl hkr Jcefsqm bjd nmunkwdjn Bgfpbzil dfc nus Iwqshc fr wnw Rtfsc


f(x)=cos⁡(x)f(x)=\cos(x)


Sfctasl



Yjpmxkg ecu Bicctst bwn mgbpbnlxh Vusamtui wys dkq Csrspa dp yun Cnufm


f(x)=−cos⁡(x)f(x)=-\cos(x)


Oljambd



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