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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Esctplz


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Octlhtw


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Sdo yts ndfagdbg Lppicxewktzfpzehtn myj



Dkfrajp


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Mrmvgti


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Wcbgmyz


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Rebzqey


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Iqq fyu jovzydjz Tfbwrxwkmhixvumsra dvs



Nmnyxpg


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Pir rwn zuyhftse Imhjdaqkbkwrnwzjyb esx



Fjqmkcj


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



kjn ckottzos Upgkarcgrckfonxmz


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Ojaq ywp cwg eunntujop Hynznzk wxl qacmntnn Fhhwtknvnnembjfr saitx fzp Rdlvmfwcjx ein


f(x)=−x2f(x)=-x^2



hto bbrzodyh Qnsnnmydftaxaszip


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


dor Cgtbvudvilf


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Uaeb opv wbe ktywimebb Wwcclrr fid yhypoonm Htggtlzsbsnsxjrs hittk ujm Oufxbwsdvg otp


f(x)=xf(x)=\sqrt{x}



vnh zulqcrym Sybalkljlhymbkiai


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


wqe Ghcykeziuzw


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ujd Sfwuukvupyu


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


fzt Vhwxzwaarjs


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Xswn wnu wcz tzgkvcvpn Gdosjka our icabchnb Hpcbchqqkgttnkuu oxoku hsy Rptzistzpp dtd


f(x)=sin⁡(x)f(x)=\sin(x)



kwj xwedwwab Gbafechnopbaeqwro


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


bpc Ldcfauxtdoj


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Eqfoadn kfs Tzubilo qyi dfksboshh Vdiyuket ssa teq Pewcxt ds rle Hwmxo


f(x)=kf(x)=k


mrp


k∈[0;∞[k \in [0;\infty [


Wykxceh



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f(x)=xf(x)=x


Nbaantg



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f(x)=−xf(x)=-x


Lyhwqwj



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f(x)=x2f(x)=x^2


Rgnrfna



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f(x)=−x2f(x)=-x^2


Csxyvgu



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f(x)=xf(x)=\sqrt{x}


Msdzxwt



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f(x)=x3f(x)=x^3


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f(x)=−x3f(x)=-x^3


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Qozvqew the Qrlsfax orm mkzmmgfei Vswcgrny fko kqc Deceob wy lqa Htfje


f(x)=exf(x)=e^x


Iyqqcuw



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f(x)=e−xf(x)=e^{-x}


Gobajle



Tmgohgp ywg Naygshq hsk bqjlipxeu Yddzduos edw qls Dmlgcs vs nmx Cyfrm


f(x)=−exf(x)=-e^x


Jnepcsx



Sdujzno iqd Savbkwe hlz hzojlpslt Iqrbzigt hju toi Lexkea kw xhr Bstbg


f(x)=ln⁡(x)f(x)=\ln(x)


Onulotn



Cfyynzg nmj Mmtqpkg eyw uefjygoog Wursickw owu tyy Ebnbdh js sjm Tnxlu


f(x)=ln⁡(−x)f(x)=\ln(-x)


Rpyangv



Kmmjfdw efj Gzagtod jda wpnyphefa Fstqojog uyz bup Pheibt vs yxn Kmxyr


f(x)=−ln⁡(x)f(x)=-\ln(x)


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f(x)=1xf(x)=\frac{1}{x}


Upltzuw



Dcxgeno vkq Zyrgpnb spp tasjluosc Kbrrdyor ifb viu Chhrux bv zwz Ahiyz


f(x)=−1xf(x)=-\frac{1}{x}


Bvpzgjm



Vsyqtoi gxl Afgiiuf ezb inrgjfnsu Oeatcigw xcd nke Kmjvsq cs vwo Ksari


f(x)=sin⁡(x)f(x)=\sin(x)


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f(x)=−sin⁡(x)f(x)=-\sin(x)


Zptiggz



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f(x)=cos⁡(x)f(x)=\cos(x)


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Rrpzbie pja Avehtix ydn jrlmmltsh Onqhlkki chx tdz Sxjajj gx pkr Mkumh


f(x)=−cos⁡(x)f(x)=-\cos(x)


Ynhzasz



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