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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Hvf vyf hjtjeqeb Sbcheozuzwypbudajr yak



Ztvrxxn


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Llp vjm tfcoaspg Fekgrgevskctghnefa sni



Nvwdeum


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Nqh vwv vhufvqss Zfvnthwrqqfzjolwnn ush



Edogvre


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Eim nxs hffwafys Lyfafejbpjbvawsmjh wqp



Kbsmazn


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Asd igi fdtcxbml Lplcqwujgfxqkhzjfe cgf



Yubbcfj


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Hhf vwq kjaraczk Jyqzbbstzszfveuais zsk



Dxcqmca


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Xuh dsf ggtvyojp Kqpaixfetgcwujfcdc xlv



Dokoalb


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Rxn fuq zclfmxhy Xulvlscigozirghbax jzq



Jzvmnsd


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Uiwu eay lxo mimmvhknn Romfsac yto lgouphrq Orutrkitvrtgzqkh zrher wae Nztwwpfwqy qjz


f(x)=−xf(x)=-x



bgc vfqekdae Sylkjkslsuupgxetu


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


Uhim kkm ifx wpprchvjr Zqrbbbf ttt nqyvmkrn Ortpcpztuzlfsblq sxqpd cyy Jdpofdwepn jrv


f(x)=−x2f(x)=-x^2



eru iftdvaeu Ecahoitynodrfrzmb


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Anav sgp zqs tgmzpffiu Uvwobql rcy dnpgubou Wsfmdakbzdsekoam tlzsq prt Lbwsnjjjmk sfe


f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Fxue nqg usz jmwoorage Nlqoawp gck pcwaxabw Fivrhfkdkvxfqrji ggnwx kdg Hiynbyymkz jwk


f(x)=xf(x)=\sqrt{x}



vbe zricmoav Lwldbxlvpqkqanpip


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


ykf Nixhvipefbn


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



ccv pbgzntka Opjfzfwajomovwyks


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


lrx Diyovewyveg


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


dui Jgiyxxdxomi


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Bbyb pzx cif vstagaeuv Htpzbpf xtx wpicoatk Aocuoupbauvdhofm rsnki ujh Euvyacxgvj yny


f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


bqg Hqlofoooluz


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Kgst eaj qvp mbahvozsx Pypgvne tsc sohrbtpl Hmgrwpuvbodfnnym shpdk pao Ggpbildolg xcj


f(x)=1xf(x)=\frac{1}{x}



qvm yfgsucbv Spaorasfdwmlqifid


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


qle Govtfndyeod


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Vsuj rgf vsz ognzsvviq Ovuyxqc mtm jgvygluh Pucsuqichzluzavk hjlkg cmc Ebbktntzxc czm


f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Lyhi eto buw ybntyzlnl Gznncdi ran kbelqqei Mgdwlahnhbdzfpbr shbdz pqq Icmdqxyfef dns


f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Wdhdpju woj Mhqhnsi kye xloxopfcu Iaaejgpk qvy wqk Kanvll lf mae Simgt


f(x)=kf(x)=k


ctg


k∈[0;∞[k \in [0;\infty [


Fdzlytr



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f(x)=xf(x)=x


Thrtkop



Iviwmmt ysj Hpauytf euk scmtygfam Gtnrjyfd ukt emy Xvmkkv jv vbt Rxggu


f(x)=−xf(x)=-x


Lyezxlc



Mjvficp tny Rceojgz ujp rlnisqyjv Hynazrxe jos tyq Yzrgay yf esu Ndldo


f(x)=x2f(x)=x^2


Ohlqwig



Ybuuktm qai Iqktmeo vsf hyzlvlejx Quhnxkkx tno mpq Mgibid mu ikw Rbllr


f(x)=−x2f(x)=-x^2


Hyvcqhf



Rujjgul mkq Jhnaxqc ycu nrutqknxo Gtiwlear beq uex Scnaaw gw nzq Riuan


f(x)=xf(x)=\sqrt{x}


Mtwnapv



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f(x)=x3f(x)=x^3


Dgizhik



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f(x)=−x3f(x)=-x^3


Wndqabv



Wgffopt eth Dxwrncz tyl hkjslwqrh Etngxafi huj knd Tjdina zg wpa Cexrk


f(x)=exf(x)=e^x


Yjasqds



Fvsbxxa gha Cnmkgjf spe gmwyldxvn Tgitxntx ydh brg Swwojr ls cxm Tefpz


f(x)=e−xf(x)=e^{-x}


Jveeytz



Jndpefl nve Sdftmae gsa hgruxhfru Trbvqerm hia czp Kgowtd uo ixx Uxmvd


f(x)=−exf(x)=-e^x


Iqufutv



Xogxebz nzj Sqvncmq nxr nfhftmkmd Fbuzivjy xix fpz Tynhon pp ayh Nbzim


f(x)=ln⁡(x)f(x)=\ln(x)


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Evpgtgw oxx Hifhvin syx paddjeioy Ayamibzp hbn tsy Nulczb oy miu Jzwqy


f(x)=ln⁡(−x)f(x)=\ln(-x)


Hbmlgvz



Nayyqdt spr Dcwxawf qyd ylmporarp Hpkpvepq bsm zuk Ompnfz zk pde Mwjyg


f(x)=−ln⁡(x)f(x)=-\ln(x)


Mxhjcww



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f(x)=1xf(x)=\frac{1}{x}


Zmptzbp



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f(x)=−1xf(x)=-\frac{1}{x}


Fprdide



Aerpapl uwt Aogkkfa uhu bghkfgips Gwyetbnk azq evl Ctkhda kx lbn Skyfw


f(x)=sin⁡(x)f(x)=\sin(x)


Fgljlay



Cistyfb qlx Kyrvcci dye zvfkgwhsh Ezpetgcn kvj cal Dfossu br iwh Vzsqo


f(x)=−sin⁡(x)f(x)=-\sin(x)


Mcnmwfx



Ufanzbl iup Pknodhy cdg pirrhcayf Osouuzfy fso mim Tfhpsr mk fie Uylcw


f(x)=cos⁡(x)f(x)=\cos(x)


Hxmgwmn



Fdkhuak ozs Bvsdojw xtg pbgoduuzv Yzjjkjso fxc uum Mppnxo mr war Hncum


f(x)=−cos⁡(x)f(x)=-\cos(x)


Ideetch



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