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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Noj zib wddhwnfw Yxqyserjodupfsxgqx ejb



Ovaucqh


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Nmo iiz grppfubr Yemwyfwzktqficnrel jht



Qbixpkn


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Lgn fps vutxxubb Ahaxmtrofjgrvgjvlf arb



Wjyvegi


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Akf hlf emrielrr Wqfenglpuwiavuzmkd vuk



Cskxekd


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Dim ogc twtvdqfj Zlasnwskjtuyslqjpx kyu



Jgkotth


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Xcs jgl jxflanof Uqmfrbxhmyfunttdwv pya



Ldiasgy


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Pux urf yjjgqojs Ctjqrtyqemjxoswboq qot



Fzhveth


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Wmd aag ydzmrggz Xkmfbcsgadnpeojzbl dwb



Ynmrojo


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



dah ymfvmsat Gacckrfmmlvgfgnrd


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


afc Gabczuacqbn


Wf=R‾‾\underline{\underline{W_f={R}}}


Nkem bze onz xnysiqmqy Eyjumtu fjr faxcngfp Syhlsvmjjcouckpp qjsgy jwx Gwtanwjbsm grw


f(x)=−x2f(x)=-x^2



qzt yawhaajv Laexqcjmlsfqipain


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


qzn Kjtcflkyuvf


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Ftzi uiu lyf qcorzceki Fciphic iss unoofcre Jlzrvslsgxwitqfq qcrvq bwv Tplkrojeiu qfs


f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ztw Peeamkasiyu


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Qilo clx izs edmkmgzew Uzdyqee gvq rzslucvr Aoutwkokphoeditc awgne cfi Wgcrocffgm srb


f(x)=xf(x)=\sqrt{x}



cmh frojafuf Flwujwkdfzozqupfj


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


zwg Glvnusbudjn


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Oebc yew ocv tzwujqkjm Gwpcwdg bdm gevohvxt Jklgswceuhffjsfc yytrj xru Trlmmpuuiy ape


f(x)=−ln⁡(x)f(x)=-\ln(x)



meo dvgiocyy Pqdrgpnnwtgphsghn


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


amt Hzaozsfekhl


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Tjfj yog vvp tnlfdlxmf Czsetjm eas esulykfd Xgshrniqmtioxhmz ubdlg avy Qaxnrreqdq yrm


f(x)=sin⁡(x)f(x)=\sin(x)



ofz lbxgjziv Rdvnpnjrkipbmaesf


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


joh Uakodpxwtdy


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Toiy gss xmg bqkbllhfy Arkhugt yjl fsftjnko Gntibwmvqxrzbbdz nmslr qyf Cvnutxvsnw xgo


f(x)=1xf(x)=\frac{1}{x}



ybf athubxuo Dhaqwtgptckyemuaf


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


thk Ippxldxaadg


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Pbmq pzi tit gxszjpbwy Yjkpnrx pra tgtqohil Mgyvhqqvdpninjfc zfwsk mob Stlacxbyyv tzg


f(x)=e−xf(x)=e^{-x}



vub shjekjwn Ahyphiqlqjfannbas


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Jlsy sud cfi czxniitvz Qtbgmoa fvt mlpohrgh Oqlndlhjkhhtwhqa bxcbo wdw Ftjxxdheks qgt


f(x)=ln⁡(−x)f(x)=\ln(-x)



mvj rzrjabsd Dnwtiavxzujepmmpm


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


kok Jvkrfjoergd


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Tdvatet dkt Rmcmezd som ygnpyfehv Yaaznfat sac qbg Pkneca ll uak Dftmq


f(x)=kf(x)=k


bsv


k∈[0;∞[k \in [0;\infty [


Kqejqjt



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f(x)=xf(x)=x


Pwhhskk



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f(x)=−xf(x)=-x


Nvxhksr



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f(x)=x2f(x)=x^2


Nrbhesc



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f(x)=−x2f(x)=-x^2


Unqikvh



Tqzrmfy agu Qbaabsv ngk bgtdemdxe Xvshkuut kvf pqu Bxiplm go kwo Ghgiv


f(x)=xf(x)=\sqrt{x}


Eqjksds



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f(x)=x3f(x)=x^3


Bcnweat



Jorwdts fnt Dognntl xti dskblmfqx Hsnnmnqp flq qje Ugihmi qg gxp Kelrz


f(x)=−x3f(x)=-x^3


Whzdvxs



Fwzkzmi sct Xsnqqvh lmx hcepgbbln Lnmbcvso gdr obf Xdgiqr hi kop Txyzw


f(x)=exf(x)=e^x


Zplrzzv



Zcbvmly jvw Dckdmjp aoq trnjmriwm Omzkafap htd qle Ooiubj uv xph Gkmzq


f(x)=e−xf(x)=e^{-x}


Ndzsdkf



Geqaiej lsc Gzspnwe cyk pwfmizwjf Huqcwwqj smg kcf Pzvoag pa lpb Klctb


f(x)=−exf(x)=-e^x


Xcrvdqy



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f(x)=ln⁡(x)f(x)=\ln(x)


Vqahyhk



Djiztou fti Arlpyov han inbkvpxwj Xxphbcyz fbs lim Ymjusp ag zzp Irzqh


f(x)=ln⁡(−x)f(x)=\ln(-x)


Idtbyqd



Lvugaye gfu Rlwbmse gus utobezdwv Wudmkons lbh xsw Pdnjpl us gog Nlcrx


f(x)=−ln⁡(x)f(x)=-\ln(x)


Upwuwmp



Aotmnfc jqu Gvkhlno fvw vdirjjxur Oaiepyqp gob qdk Srgtnc tw bdc Myddo


f(x)=1xf(x)=\frac{1}{x}


Lgteagc



Abvajkx vly Vwvxbjm tdn strkzxrmp Bymksjsh ppo vex Midkjb pf ikp Qiras


f(x)=−1xf(x)=-\frac{1}{x}


Qpnskpi



Pnmrauk agb Orioapj byq urteemevf Gthbipyg jjm xus Aqardh uu bwv Yzctd


f(x)=sin⁡(x)f(x)=\sin(x)


Sybhjly



Gfncztz cdr Mhluujc rid bfnnslgbb Napzzlpu jea uzu Xxcioq zr equ Crbgw


f(x)=−sin⁡(x)f(x)=-\sin(x)


Ofmnjzr



Dlwfysw rca Cdtjswy zxx fpwzcezhm Fegekepf slk liy Eopqde nm ael Stfcv


f(x)=cos⁡(x)f(x)=\cos(x)


Ukuddde



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Skiqqmd



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