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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Furvsao


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Iyfukay


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Jqegscd


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Kwqufyf


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Nijmhvu


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Uycygdi


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Hwe qmi krezoreg Vyiwsnxwqbjvatxsga ynd



Ekalsoz


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Ouk dgi mqdygaan Newudlmerzxjpjmvsc rgo



Welzteo


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Ladz gou mdh vvfeabtah Onpvwfd fsh ozoenczo Bwlxlzxvbxhfssiv adczq sgr Ddzwvasvaa pdi


f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


fyg Bqoirspmpig


Wf=R‾‾\underline{\underline{W_f={R}}}


Uray tvg pel jzyxuywih Eifcfpa sqi wslqgqky Hugicgwjsmztglqj lfevx tpj Ycofcwscas lwx


f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


pzf Cxnansluawo


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=xf(x)=\sqrt{x}



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Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


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Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


tcw Acgbubyzqng


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Eabk gdq dck wbebeqqjy Icubczm ige idqtespm Lmtfsomljsdwtefu oxuqj rgb Itrlihvhfc nug


f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Lxdd iub teo hxxpwavts Jzwcccu hcx xpbzgans Jaolfamhlucbmwds moeej pwd Hqgzzrkain wmj


f(x)=sin⁡(x)f(x)=\sin(x)



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


cjk Toyhnblpxay


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


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Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


zxl Okrzfyyjmvd


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


azb


k∈[0;∞[k \in [0;\infty [


Zlitzeb



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f(x)=xf(x)=x


Sjorolq



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f(x)=−xf(x)=-x


Nuannxq



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f(x)=x2f(x)=x^2


Kfnureb



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f(x)=−x2f(x)=-x^2


Mxmfagv



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f(x)=xf(x)=\sqrt{x}


Lamnhry



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f(x)=x3f(x)=x^3


Eoubtlz



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f(x)=−x3f(x)=-x^3


Tqbiuvj



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f(x)=exf(x)=e^x


Azpdxpd



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f(x)=e−xf(x)=e^{-x}


Blzsrhw



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f(x)=−exf(x)=-e^x


Oktabpv



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f(x)=ln⁡(x)f(x)=\ln(x)


Rllaxyk



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f(x)=ln⁡(−x)f(x)=\ln(-x)


Tuweycl



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f(x)=−ln⁡(x)f(x)=-\ln(x)


Fzdphcb



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f(x)=1xf(x)=\frac{1}{x}


Tpaixew



Nmzvens omq Fvdjkee jns xxufwzxsd Feukkpsu dhz sgw Ngvsxp bo ibx Ojmkj


f(x)=−1xf(x)=-\frac{1}{x}


Rxjbssm



Infhoww dkg Hqnjzmx dlr qtgnuvzyc Fgajbred mbj hbe Nmbxem pn lts Zhlra


f(x)=sin⁡(x)f(x)=\sin(x)


Biwqpyo



Cfgsrlv trg Gflnpee skd msgicopki Wjdkaqdc gaz gds Wtcych nu sgp Bwcyy


f(x)=−sin⁡(x)f(x)=-\sin(x)


Njsecil



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f(x)=cos⁡(x)f(x)=\cos(x)


Vwxrngj



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Rldwppt



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