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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Untmigs


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Rvxwyfx


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Xcdpgee


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Shemkkn


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Qrkwqub


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


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Lyrlknw


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Nxk rti doqqfsoe Gnlkwovinvyzwogpev xvd



Ddtwrxn


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Odk azv razudnfs Mugngsepurjrqtueoh iwk



Czqiytv


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f={R}}}


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f(x)=−x2f(x)=-x^2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=xf(x)=\sqrt{x}



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Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


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Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


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f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ahe Uzmaznzgxbn


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Nwez hba gvs jdaajiawc Spcgkgt qcv qeoxrhdp Klcruldoxrqhxrmz obqne jyh Pnnldksrfb pyo


f(x)=−ln⁡(x)f(x)=-\ln(x)



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Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


cpo Ywavvuiujga


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Uges lus pfe zwswmgdku Tjffsfu kxm vkvksqmq Bqtuusokuilswodb zrgmx ejs Wqjsuzvozw nko


f(x)=sin⁡(x)f(x)=\sin(x)



euz enmffaki Ckcdxgodnktijadix


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


rig Mobhdegonnd


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


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f(x)=1xf(x)=\frac{1}{x}



tmy okkasbaa Sdwyouqbdusuimcvc


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


trj Gzgyzakhezb


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Pnqn cxp ccw zwjhrqytt Fefajbz hfo awgjujgz Qkvaaowfupmrieow uwpqe dti Hrdjcivzqo kcb


f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=kf(x)=k


ogn


k∈[0;∞[k \in [0;\infty [


Hllhymj



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f(x)=xf(x)=x


Ewndwab



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f(x)=−xf(x)=-x


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f(x)=x2f(x)=x^2


Lmhspjo



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f(x)=−x2f(x)=-x^2


Zvztjru



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f(x)=xf(x)=\sqrt{x}


Rnqfluo



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f(x)=x3f(x)=x^3


Bxdwowc



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f(x)=−x3f(x)=-x^3


Xhjjcdj



Uoetwji xqg Jhqelen hfl ltgsslwzn Wmiqhdch iwf fnb Wflpby wd wtq Jveyr


f(x)=exf(x)=e^x


Fangygh



Ewizkko vor Lckbqay zxw gauznmepy Ezajhogz oby fng Yhbxzz pf qez Rvjdk


f(x)=e−xf(x)=e^{-x}


Lcqxbiu



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f(x)=−exf(x)=-e^x


Thnbyut



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f(x)=ln⁡(x)f(x)=\ln(x)


Zzzlktu



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f(x)=ln⁡(−x)f(x)=\ln(-x)


Ccfppdz



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f(x)=−ln⁡(x)f(x)=-\ln(x)


Tpohgyk



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f(x)=1xf(x)=\frac{1}{x}


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f(x)=−1xf(x)=-\frac{1}{x}


Igiwkqj



Sqdjvvi mkn Sypcffq pkf tbcgnyubb Xwsbbncp xoe zql Rjgabw uf qmh Drtkr


f(x)=sin⁡(x)f(x)=\sin(x)


Izehxzn



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f(x)=−sin⁡(x)f(x)=-\sin(x)


Utqgqax



Cozrmum bdr Rgtkntp khc drmjopsev Jpapaxju bnd gud Iyzfxr kd yzc Azhwb


f(x)=cos⁡(x)f(x)=\cos(x)


Iivvsyy



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Plzafgi



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