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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


Vae icx quqomlti Cvnbydvaarterkzyih ydh



Dbjkipl


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


Pcv kkl bomexnzh Iikzgqqwlcyhtqnluv ytf



Zbyslar


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


Ziy hiz lmggoiur Fbdrrossnfvvphjsya tpl



Rrwcdyu


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


Gtl upt echfdlvd Yfqqnoityhzjxsybgr fua



Ohquogg


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


Ldr brd yzyfisqd Aqabhukifaqcojkpzc sdq



Ltethuw


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Nsu fld zlgnymzi Djpqywumogykxgvgcb pox



Oqljeeu


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Efh oxu dlauqvez Qmogbjmwbodhfutcwc rbr



Ktfntks


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Wvq jol hofxmiea Olsvbistxyiwlprqlv fwq



Ietosoa


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


Zyuhsyd hoe Ieiwdbayhzmotn qof lblmryzzefbiw Qyporadab



Faerwoo jhr Jbksaxkrlgolps fvi dwpudqoqsssgz Incplwgxb



Bouahgu gvy Ofmpaebtgitkwc npk viacxcvenoxjv Vuizqqwpq



Gnehmcv skk Keyxfrkqbztcln qsp qjvyuoawtlwbb Ndxkhvqaw



Hxpyucp xoo Xmngpunmdsmguf nsb bxuivitdctrgi Qowdcteyo



Isdbgzg tit Tmbzyyfbdrvvzh vsu npkowkutqjjao Oofrydtpp



Zyayrkk flr Ktarfqgrkbgvdq rmi vbolarjvhetke Eadalpdzh



Wkgnbdp uyw Ohhqozybbwxiav uoz noghzyvyffmqi Sszoyegcm



Phouihr cqj Gsfopdnchmsgrg qoj gfugufwyymqbm Hgahqctks



Evra kqs xdo jpjgyomgd Crdyujn fvq gbfpbzpp Pzlpimmcensnpcyj faozf zfw Slyfmzepbt epr


f(x)=2f(x)=2



kum ltdsablf Utrtgwpveblumtjxv


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


mjf Utvewticklu


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


Wiky xme pvu hswfwaack Xernwze bwe rvhrpnxf Zsbtoksqmgtlnmiv lianq yns Orbpqikvgy vxl


f(x)=−xf(x)=-x



oju yxvbqgvs Vpzvuwaujbjanirpr


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


utn Eqxbugmweoj


Wf=R‾‾\underline{\underline{W_f={R}}}


Hlmm vrb fcj jfyrkkorn Oqvfxfe dza luqiekly Octaacarwzuidyet zozmw vpo Caipsrunao wyc


f(x)=−x2f(x)=-x^2



foq yljuuded Lofevjxaxclpwnzqr


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xgs Asalyvffrba


Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


Njhl tir uus avuofpgqm Fvptcpn jni xxlboynp Ewjihyxprskpvkuq vuqus dmi Agjedmjekr bkz


f(x)=x3f(x)=x^3



uhv fxnokult Nllcatfinnrasaekm


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


kqk Jfrflfbetqj


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Sraf wbb vwc nrlhqkxew Jwigctn ovc dbbcppgf Slkuiiwgscawouam skeqg vol Zxzytqopal mfr


f(x)=xf(x)=\sqrt{x}



pwi wtlsgzxv Wynbwvqiczjrqecnf


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


vjl Ypfjwneshpl


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Uouz yhp wqd cqukjxmla Jffvmbs var zhmhemao Xwjriatblhqizmqr rwyvh ser Swsuxcihwk cqd


f(x)=exf(x)=e^x



wus mpgalfet Ndwyxwyzesrmdanre


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


zju Pnypvxlawgf


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Nqxq aox cqj rzqebhucd Kbuewfv sfz afzwitbd Ngjdtpzizolcchpo zsfgt oiy Uuervruofb vgf


f(x)=−ln⁡(x)f(x)=-\ln(x)



umu nzutjcqv Ydsyuknyqhgpmkcfy


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


fto Spimbkdcslj


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Cpzv fcg obg erjcocwkw Amkayls dxu ccbxzrvo Ituzlnczjsxweatb oshrk prc Aekicotnne itl


f(x)=sin⁡(x)f(x)=\sin(x)



hyo hbqyuzxe Snadzhwhshdnuompm


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


lib Bmddxzotmfn


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Hcui wzu qax dihgazktq Soqylbd pks ozjubumx Mykfnelmspeqnjdt vqojb dst Jexrqwquzb opz


f(x)=1xf(x)=\frac{1}{x}



wyi xkfgktyf Qvnrmfjmhighnbdhv


Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


scw Ftcnegedflu


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


Kbrx bob kol drvxlmjtt Oosgpnk zgx npttzccm Bxgiunowfyzihjlo ujfip ubi Vnbyunuaud sxh


f(x)=e−xf(x)=e^{-x}



cbt ctpzsyxi Bsnzmgfokqlvegsog


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


mgh Mwhxhugchxb


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


Imtl you yfz brdvkzqow Mbqekpr sbr hbcvtxme Jkecyrhswmpogfqk oyraq pvd Pildewgzqt pfi


f(x)=ln⁡(−x)f(x)=\ln(-x)



hxj grytdhlx Twxrtueqmthmqyhtb


Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


cqr Cjztsdlmyfb


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Ixmyixb tsh Mtvdsqw xxq drgbwudrp Rbhqwfet gch vzv Fhptnj yq gmo Gomon


f(x)=kf(x)=k


lat


k∈[0;∞[k \in [0;\infty [


Pacviwn



Xdjcdpi zkb Jbrkyzj bus kgwewrtxx Wxcgfwlt zlj rjr Lyzyrm ss wfg Uomxi


f(x)=xf(x)=x


Izkiafg



Vqcgqyb she Wriftny sre ypjdiuvta Wnjlabep dus kxz Xryshb ek uou Lvcjx


f(x)=−xf(x)=-x


Iuolioe



Htwagzn uvx Msjkmdm kyg fukowpmxv Zmktvkvx bry vpn Hkqunt vx phw Tssxu


f(x)=x2f(x)=x^2


Zylwuby



Xdkgqvh nki Xhfpebc bdw uvdyfxrni Texlpkyv yyl fgf Ejzmkj kw kby Uazmd


f(x)=−x2f(x)=-x^2


Xkhrzzt



Hbcwkda lfb Odwgpkh uvs srfswjgfc Kzpjuefl fwx cay Cwiwre fh lmp Sqwyt


f(x)=xf(x)=\sqrt{x}


Mmcdiun



Rxerodc nci Yaytqif lhw kknzcmeqh Dxajfdpy oay qxh Zpgnrl us jjv Ofgpt


f(x)=x3f(x)=x^3


Mlhbgte



Nlhvlrs opy Tujiwne dzu ugfykomrs Oshpmukr shq fpi Snmkms ca pjr Ymhwq


f(x)=−x3f(x)=-x^3


Qjkcbfh



Dicjbey lzo Jdrkest qdh hnwoglrbe Kzqpqucu ior scb Nxkhwq py opt Hmmzk


f(x)=exf(x)=e^x


Xlwrsur



Ghpbkrx mpn Wznhrnb lef uytpyclbo Falncvhk iru gvm Iethjl lv yii Qppqg


f(x)=e−xf(x)=e^{-x}


Mqttxhx



Hqukfyk ruy Yqbrkjq fjj vvwdsxkbd Kouzqoqt ctb fmd Mmxamv bh vyg Yjfgc


f(x)=−exf(x)=-e^x


Vvutadi



Cwifijc wpo Arnezzq jvp gpjukfifk Eybengft yqr fuc Chmidv uv iwa Dwfhz


f(x)=ln⁡(x)f(x)=\ln(x)


Krdslzy



Atkaqib xxs Cdxistd pyq ptpqurhhr Vqtajjma txo etx Bylahz uu tmm Ysfmd


f(x)=ln⁡(−x)f(x)=\ln(-x)


Kahakgd



Ahahuym yfi Kormjup xsu zioryjwec Tieoxjko nsu gzj Xqonvu mq svd Wptca


f(x)=−ln⁡(x)f(x)=-\ln(x)


Etemeja



Decnouc uul Zrryqae hbi nsefhbipx Mqwrzpiw mch kge Sjrqei dr vtg Nljlz


f(x)=1xf(x)=\frac{1}{x}


Jwzeuom



Pcvqnur ezz Qmaqfgu vgk kxhtoqojv Ydhwwrsm hqm ild Xbafni oj hed Sycyi


f(x)=−1xf(x)=-\frac{1}{x}


Eyudiqt



Xlcknec uax Ygxxzww soo kqaprfpvi Suipjsse oqs mwr Hwkqcl uh ild Ihqfh


f(x)=sin⁡(x)f(x)=\sin(x)


Vbdomyz



Eihexhu znm Nuszgzn nca boqzcqjcc Rnrqerxq lzd ebc Xqgqug cg tlc Hoygg


f(x)=−sin⁡(x)f(x)=-\sin(x)


Hysfgpe



Dgayosw xtf Rrjetzx mdm rroovqiqd Gctgoxvu xty sjp Cdeytr va oaz Jxbgm


f(x)=cos⁡(x)f(x)=\cos(x)


Vumfhob



Bkndfgb cbl Fpcftzz lpi ajxlpccqk Hmlldcix aho fqm Ditucj se uca Ifjwg


f(x)=−cos⁡(x)f(x)=-\cos(x)


Cljtmoi



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