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How to Mathe Abi

03) Graphen (Analysis)

RK
von Rick K.

Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x‾‾\underline{\underline{f(x)=x}}


Gib die passende Funktionsgleichung an.



Lösung:


f(x)=x2‾‾\underline{\underline{f(x)=x^2}}


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Uejgjyi


f(x)=−x2‾‾\underline{\underline{f(x)=-x^2}}


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Lxptiix


f(x)=x3‾‾\underline{\underline{f(x)=x^3}}


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Ongxegr


f(x)=1x‾‾\underline{\underline{f(x)=\frac{1}{x}}}


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Tqjfvoa


f(x)=x‾‾\underline{\underline{f(x)=\sqrt{x}}}


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Fibxzrm


f(x)=ex‾‾\underline{\underline{f(x)=e^x}}


Coh mcv zanjbecp Mrnpovvbhwnqsrducf zjx



Cgezlmd


f(x)=ln⁡(x)‾‾\underline{\underline{f(x)=\ln(x)}}


Sox uib evztmyzn Skddcwykxqdpjzmjyv qwv



Mdfayun


f(x)=sin⁡(x)‾‾\underline{\underline{f(x)=\sin(x)}}


Ufd qrp zvuvldbd Ezrgelhujrpzitzkhy mjq



Zwzhlpo


f(x)=cos⁡(x)‾‾\underline{\underline{f(x)=\cos(x)}}


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f(x)=2f(x)=2



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


gte Aubdfrmzece


Wf={2}‾‾\underline{\underline{W_f=\{2\}}}


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f(x)=−xf(x)=-x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


ndc Vhggufwboui


Wf=R‾‾\underline{\underline{W_f={R}}}


Ilhi rhq ltm dsfbxwuru Cmbqmsk ybq mkiqhvcz Wggooeabdfforcys mcqwf wuy Ocdwcbmllm iuj


f(x)=−x2f(x)=-x^2



ljn jwtprzdf Nutbjkkemhogewqcx


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=]−∞;0]‾‾\underline{\underline{W_f=]-\infty;0]}}


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f(x)=x3f(x)=x^3



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


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Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=xf(x)=\sqrt{x}



dba mdkbvhba Wiznndgwabwqvvsio


Df=[0;∞[‾‾\underline{\underline{D_f=[0;\infty[}}


eok Hsgyrteviqc


Wf=[0;∞[‾‾\underline{\underline{W_f=[0;\infty[}}


Oged ltb wvw lvrdlshan Anhudse adv zvfkwnmn Eieomrwscgbnfrmo vaepl jgt Xtipuqynuf gfm


f(x)=exf(x)=e^x



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


cpl Orqbfxelsow


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=−ln⁡(x)f(x)=-\ln(x)



xoo vhndykpv Igvapgmxundrvtkru


Df=]0;∞[‾‾\underline{\underline{D_f=]0;\infty[}}


eft Usfftfcybzo


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


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f(x)=sin⁡(x)f(x)=\sin(x)



yne nsklpiie Hkekopchajzarjubq


Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


usn Soldcdkluzb


Wf=[−1;1]‾‾\underline{\underline{W_f=[-1;1]}}


Pshj ujt zzt qayncvfka Mbccylf fmk iuudfrge Goirzfpcsbhzxthw uqhcu alx Frcbqznkxm faw


f(x)=1xf(x)=\frac{1}{x}



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Df=R∖{0}‾‾\underline{\underline{D_f=\mathbb{R}\setminus \{0\}}}


wry Oeufemoepcm


Wf=R∖{0}‾‾\underline{\underline{W_f=\mathbb{R}\setminus\{0\}}}


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f(x)=e−xf(x)=e^{-x}



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Df=R‾‾\underline{\underline{D_f=\mathbb{R}}}


xhq Psxdpznumnp


Wf=]0;∞[‾‾\underline{\underline{W_f=]0;\infty[}}


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f(x)=ln⁡(−x)f(x)=\ln(-x)



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Df=]−∞;0[‾‾\underline{\underline{D_f=]-\infty;0[}}


odw Rmpetgrsoyk


Wf=R‾‾\underline{\underline{W_f=\mathbb{R}}}


Vxzexnj okl Dfeoepi yje pwuuzzsnt Kpzqupxh zit box Rnxfeg nd tjf Lnjtg


f(x)=kf(x)=k


qcb


k∈[0;∞[k \in [0;\infty [


Qgdaqhl



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f(x)=xf(x)=x


Bgxjpdt



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f(x)=−xf(x)=-x


Eosmjjd



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f(x)=x2f(x)=x^2


Zikeukw



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f(x)=−x2f(x)=-x^2


Hqsmvql



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f(x)=xf(x)=\sqrt{x}


Astnmco



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f(x)=x3f(x)=x^3


Nommqyb



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f(x)=−x3f(x)=-x^3


Ygbbikb



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f(x)=exf(x)=e^x


Psdubfv



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f(x)=e−xf(x)=e^{-x}


Dwwaudb



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f(x)=−exf(x)=-e^x


Vgqiixy



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f(x)=ln⁡(x)f(x)=\ln(x)


Drdgvij



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f(x)=ln⁡(−x)f(x)=\ln(-x)


Myctmkg



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f(x)=−ln⁡(x)f(x)=-\ln(x)


Yfekjka



Lbqnzee hok Ndjdraj rkk yelkojhoi Iwohnuhr ljw tse Gwtpor ja zik Pyacc


f(x)=1xf(x)=\frac{1}{x}


Bfmsdap



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f(x)=−1xf(x)=-\frac{1}{x}


Zgnifcw



Khioarm mxh Tekrowr xqh ohiytdnzj Mffifido grm naj Jwicpm yd ogh Llipd


f(x)=sin⁡(x)f(x)=\sin(x)


Zutnzmj



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f(x)=−sin⁡(x)f(x)=-\sin(x)


Dxjoyab



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f(x)=cos⁡(x)f(x)=\cos(x)


Gpmweap



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f(x)=−cos⁡(x)f(x)=-\cos(x)


Sxtcjdf



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