c
a
for some reason, A is proportional to T^1/2
so on increasing T, A also increases and thus rate constant which here is equal to A, also increases
d
b
just use limits
Stable Al has no use here
Ans is b
by doing beta emission, it gets converted to Si 14 which is stable at 29 ( ithink)
AD
AC
specific activity is activity per unit mass
thus mass of U3O8 is 833
number of mols in 1 g is 1/833
thus no. of uranium is 1/277
in 1 g uranium, mols = 1/235
Thus, activity which is proportional to number of particles, is greater in U than U3O8
Decay constant however remains the same as its dependent on the NUCLEUS which remains unaffected by chemical rxns
a??
19.2
Its just integration you can do it
This is parallel rxn eqn
Thus when OH- = 0.01
k(sn1) = 5 k(sn2)
Thus sn2 forms 1/6th of the product
4
Ans is 3
e^0.7 = 2
A. P→1,4;Q→2,5;R→1,2;S→1
B. P->2,5;Q->3,5;R->1,4;S->1
C. P->1,4;Q->2,5;R->1,4;S->1
D. P→2,5;Q→3,5;R→1;S→2,4
A. 135 min
B. 103.7 min
C. 38.7 min
D. 45 min
convert the expression to the form
d(lnK)/dT = Ea/RT^2
on multiplying both sides by T^2, we get
Ea = R(40-600/T)
Put T= 300K and you get Ea = 38
pressure is only due to the released alpha particles
in v ilute, xa = na/nb
where a -> solute
b-> solvent
its just the weighted mean
E net = (E1k1 + E2k2)/k1+k2
it should be k1 = k2 RT^n-1
its just relations between kp and kc
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