A transistor is a semiconductor device used to ….. or….. electrical signals and power.
amplify
switch
pnp
npn
the arrow always pointer on the negative
REMEBER VERY IMPORTANT
to know where is the emeter look at the middle arrow inside this circle , the place near to this arrow is always be the emeter
IC≈…
VBE=…
IE=
ß=
Alpha(α)=
Remember this
ICEO (the collector-to-emitter current with the base leg open) =
.•. IB≈0
Because ……..
IE
0.7V
IB+IC
ß= IC/IB
α= IC/IE OR IC/IE - (ICBO = I of collector) if the emitter is open(IE=0)
Then ICEO (the collector-to-emitter current with the base leg open) =
ICBO/1-α
OR
BxICBO
CEO bفcbo
Because IC=IE with different voltage(VCB)
Tell me the relation that connects Alpha with Beta
Various types of general-purpose or switching transistors:
(a) ……
(b) …..
(c) ….
low power
medium power
medium to high power.
What is the cutoff region in a BJT common-emitter configuration?
A) The collector current is at its maximum
B) The base current is zero
C) Both junctions are forward-biased
D) The collector-emitter current is very high
B
The common-collector configuration is used primarily for impedance matching purposes since it has a …. input impedance and …. output impedance,
opposite to that of the common-base and common-emitter configurations.➢ The output characteristics of the common-collector configuration are the same as for the ……. configuration
High
Low
common-emitter
Explanation: In the saturation region of a Bipolar Junction Transistor (BJT): 1. Both the base-emitter junction and the base-collector junction are forward-biased.
2. The transistor conducts heavily, and the collector current (Ic) reaches its maximum value, limited primarily by the external circuit.
3. The transistor is "fully on," acting like a closed switch.
What does a transistor tester measure?
Q point is consder ….
IB
What is the type of this circuit 👇👇
And what is the value of VE in it
= -12+IBx240x1000+0.7=0
.•. IB=✔️
= -VCC+ICxRC+VCE=0
= -12+(2.35x10^-3)x2.2x1000+VCE=0
.•. VCE=✔️
In saturation point ic=0
And in cutoff
Q point changing represented by ……
Fixed Biasing Configuration (self)
0 (so VBE=VB=0.7)
IB OR IC BECAUSE IB≈IC
If IB INCREASE SO Q POINT INCREASE AND Vice versa
What is the type of this circuit
Tell me IB and VC and VE (when write one symbol means the symbol and the ground)
Emitter-Bias Configuration
Ans 1
-20+IBx430k+0.7+IEx1K=0
Remember this to make one variable to can answer it
Ans 2
VC-VCE-IEx1K =0
Ans 3
VE =IE(IC)xRE
Note
IE≈IC
What is the type of this circuit and solve this👇👇 by Exact method
Tell me what is the IB
_____________________________
Solve same question by using approximatemethod but Tell me the condition law which tell you if you can solve it by this method or not
Voltage-divider Bias Configuration
If ƁRE =>R2
So you can use this method of solution
VB = VTh
@عند الساد sese عنده فلوس صفر
What is the value of X from the opposite figure 👇👇
VCC
IC saturation (sat)
At sat VCE =….
So RC =….
IBQ=…..
20
10
0
From kershof
25
Last changed7 days ago