denominator is (t+cos)^2 + sin^2
take e^x = t
after converting the expression in terms of t,
divide both nr and dr by t^2
solve the integral
then solve the 1^inf case
take x as 1st
xe^-x^2 as 2nd
write the integral and then expand
as the expression is indipendent of b, f(0)=f(1)
solve further
understand using area under graph
Use king’s to get sin6x/sin2x
take 2x = theta
solve futher
x must be 1 and y must be -1 in order to get sum as 9pi
seeing the limits, we realsie that we should subc x with 1/t
just direct by parts
just use king’s
divide 0 to pi/2 into two intervals,
0 to pi/4
pi/4 to pi/2
convert to sin cos
then use kings
put sec + cos = t
expand ln(1+x) and solve that integral
then do harkate to get ans
take e^x to LHS
then diff both sides
use king’s
just use king’s then open the bracket and integrate each term
can easily be factorised, think about it
differentiate integral g(t) and use L’hopital in f(x)
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