Thermo chem

d

a

Nh3 reacts with cuO to form H2o and Cu and N2

Cu and N2 have 0 enthalpy of formation

a

d

c

a

c

d

a

b

c

a

b

the c=c energy includes the c-c energy too

so when you break that bond, you break the whole db and then you need to make the c-c bond again

b

a

119 kj is released when a db is reduced

so 3*119 is released when cyclo-hex-triene is reduced

so formation of cyclo-tri-hexene adds 3(119) kj

so -156 + 3(119) + RE= 46

solve for RE

a

net energy of solution is +ve, hence endothermic

thus higher temp increases solubility

bcd

ad

a

only A

D isnt true as for it to be enthalpy of combustion, an entire mol of N2 must be combusted, here only half a mole is

Make delta ng = 0 for dH = dE

Thus ans is b

b and d

this is because in them, resonance also occurs, and so the bond energy methoid and calorimetry method give diff answers

a and b